Let x = the unknown number to get x = 6
Answer: X = 7√2
Step-by-step explanation:
Let first Consider triangle BDC,
Cos C = adjacent/ hypothenus
Cos C = 7 / x ...... (1)
Also, let consider triangle ABC
Cos C = adjacent / hypothenus
Cos C = x / 14 ....... (2)
Since angle C is the same, equate equation 1 to 2
7/ x = x / 14
Cross multiply
X^2 = 98
Make x the subject of formula
X = sqrt (98)
X = sqrt ( 49 × 2 )
X = sqrt (49) × sqrt (2)
X = 7 sqrt(2)
X = 7√2
Answer:
8+18+20x16 ,
Step-by-step explanation: yeah .
The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
Answer:
no but 1+1=2 hehe
Step-by-step explanation:
follow me on tt: dxddy.drip0