We are given : -3(4-6x) < x+5.
Solution: -3 is in front of Parenthesis.
We need to multiply -3 by (4-6x).
So, we need to applying distributive property.
On distributing, we get
-12+18x < x+5 (By distributive property)
The reverse operation of addition is subtraction. So we need to subtract x from both sides, we get
-12+18x-x < x-x+5 (By subtraction property of equality).
-12+17x < 5
Now, we need to get rid -12 from left side.
So, we need to apply addition property of equality, we need to add 12 on both sides, we get
-12+12+18x < x+5+12 (By addition property of equality)
17x < 17
We need to get rid 17 from left side. So we need to apply division property of equality.
On dividing both sides by 17, we get
17x/17 < 17/17 (By division property of equality)
x < 1.
Answer:
The graph shows the solution of the inequality y >
x - 2 ⇒ D
Step-by-step explanation:
In the inequality,
- If the sign of inequality is ≤ or ≥, then the line that represents it must be a solid line
- If the sign of inequality is < or >, then the line that represents it must be a dashed line
- If the sign of inequality is > or ≥, then the shaded area must be over the line
- If the sign of inequality is < or ≤, then the shaded area must be under the line
From the given graph
∵ The slope of the line =
=
=
= 
∵ The y-intercept is (0, -2)
∵ The line is dashed and the shaded area is over the line
→ By using the 2nd and 3rd notes above, the line is dashed and
the sign of inequality is >
∴ The inequality is y >
x - 2
∴ The graph shows the solution of the inequality y >
x - 2
By angle, you're a scalene triangle, and by angle, youre an acute triangle
Answer:
see explanation
Step-by-step explanation:
Given
2BD = 7BT , then
2(d - b ) = 7(t - b) ← distribute both sides
2d - 2b = 7t - 7b ( add 7b to both sides )
2d + 5b = 7t, thus
2
+ 5
= 7t
+
= 7t
= 7t , thus
t = 
= ![\left[\begin{array}{ccc}3\\5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Hence T = (3, 5 )
Answer:
C
Step-by-step explanation:
Since this is an indererminate form, use L'Hopital
d(sint)/dt = cos(t)
d[ln(2e^t) - 1] = (2e^t)/[2e^t - 1]
As t --> 0,
cos(0) = 1
(2e^t)/[2e^t - 1] = 2
1/2 is the limit