Let P be the population proportion, p be the sample proportion, n be the sample size.
A manufacturer claims that fewer than 6% of its fax machines are defective. It means P=0.06
Sample size n=97 and sample proportion p=0.05
The hypothesis to be tested is
H0: P ≥ 0.06 V/s Ha: P < 0.06
Here the hypothesis for testing population proportion we use z test statistics. Z test statistics is give by
Z = 
Where p =sample proportion = 0.05
p0 = hypothesized proportion value =0.06
Using given values into test statistics we get
Z = 
Z = -0.41
The p-value for left tailed alternative hypothesis is given by
P-value = P(z < z cal)
where zcal = Z test statistics value
Here zcal = -0.41
P-value = P(Z < -0.41)
Using z score table to find probability below z=-0.41
P-value = 0.3409
P-value for testing the given claim is 0.3409
I believe that it is the second and third boxes
Answer:
$8.50*x(amount of material)-$5=y (total)
Step-by-step explanation:
Given that (p - 1/p) = 4, the value of p² + 1/p² is 18. Detail below
<h3>Data obtained from the questio</h3>
- (p - 1/p) = 4
- p² + 1/p² = ?
<h3>How to determine the value of p² + 1/p²</h3>
(p - 1/p) = 4
Square both sides
(p - 1/p)² = (4)²
(p - 1/p)² = 16 ....(1)
Recall
(a - b)² = a² + b² - 2ab
Thus,
(p - 1/p)² = p² + 1/p² - (2 × p × 1/p)
(p - 1/p)² = p² + 1/p² - 2
From equation (1) above,
(p - 1/p)² = 16
Therefore,
p² + 1/p² - 2 = 16
Rearrange
p² + 1/p² = 16 + 2
p² + 1/p² = 18
Thus, the value of p² + 1/p² is 18
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