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2 years ago

Please help me. i’ll give you brainliest points

Mathematics

2 answers:

Taya2010 [7]2 years ago

6 0

Answer:

The answer would be P

monitta2 years ago

3 0

Answer:

i dont know

Step-by-step explanation:

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What is the acceleration of this object?

VMariaS [17]

Answer:

3.3m/s2

Step-by-step explanation:

7 0

3 years ago

can someone help me find the slope . and tell me how you got the steps and answer. question-What is the slope of the line that p

densk [106]

Answer:

m = -8/3

Step-by-step explanation:

Keep in mind that slope is defined as m = rise / run, or, alternatively,

m = (change in y ) / (change in x).

If we start at (-10, 8) and move to (-4, -8),

the x coordinate is seen to increase by 6 from -10 to -4, and

the y coordinate decrease by 16 from 8 to -8.

Thus, the slope of the line segment connecting these two points is

m = -16 / 6, or m = - 8/3

4 0

2 years ago

Let $\mu$ and $\sigma^2$ denote the mean and variance of the random variable x. determine $e[(x-\mu)/\sigma]$ and $e{[((x-\mu)/\

Nezavi [6.7K]

$\mathbb E\left(\dfrac{X-\mu}{\sigma}\right)=\dfrac1\sigma\mathbb E(X)-\dfrac\mu\sigma=\dfrac{\mu-\mu}\sigma=0$

$\mathbb E\bigg(\left(\dfrac{X-\mu}\sigma\right)^2\bigg)=\dfrac1{\sigma^2}\mathbb E\left(X^2-2\mu X+\mu^2\right)=\dfrac{\mathbb E(X^2)-2\mu\mathbb E(X)+\mu^2}{\sigma^2}$
$=\dfrac{\mathbb E(X^2)-2\mu^2+\mu^2}{\sigma^2}=\dfrac{\mathbb E(X^2)-\mu^2}{\sigma^2}=\dfrac{\mathbb E(X^2)-\mathbb E(X)^2}{\sigma^2}$
$=\dfrac{\mathbb V(X)}{\sigma^2}=\dfrac{\sigma^2}{\sigma^2}=1$

3 0

3 years ago

Rewrite with only sin x and cos x. <br><br> sin 3x

xeze [42]

$\bf sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\\\\\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\
cos(2\theta)=
\begin{cases}
\boxed{cos^2(\theta)-sin^2(\theta)}\\
1-2sin^2(\theta)\\
2cos^2(\theta)-1
\end{cases}\\\\
-------------------------------\\\\
sin(3x)\implies sin(2x+x)\implies sin(2x)cos(x)+cos(2x)sin(x)$

$\bf 2sin(x)cos(x)cos(x)~+~[cos^2(x)-sin^2(x)]sin(x)
\\\\\\
\stackrel{like~terms}{\stackrel{\downarrow }{2sin(x)cos^2(x)}~~+~~\stackrel{\downarrow }{sin(x)cos^2(x)}}-sin^3(x)
\\\\\\
3sin(x)cos^2(x)-sin^3(x)$

8 0

3 years ago

The cost of a pair of ice skates went from $200 to $140. What is the percent change in the cost of skates?

dmitriy555 [2]

so the pair went down from 200 to 140, so the difference is 200 - 140 = 60.

so if we take 200 as the 100%, what is 60 off of it in percentage?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 200&100\\ 60&x \end{array}\implies \cfrac{200}{60}=\cfrac{100}{x}\implies \cfrac{10}{3}=\cfrac{100}{x}\implies 10x=300 \\\\\\ x = \cfrac{300}{10}\implies x = 30$

3 0

3 years ago