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SCORPION-xisa [38]

3 years ago

8

Your favorite dog groomer charges according to your dog's weight. If your dog is 10 pounds or under, the groomer charges $30. If

your dog is between 10 and 35 pounds, she charges $40. If your dog is 35 pounds or over, she charges $1.25 per pound. You have three dogs. Max weighs 25 pounds, Sally weighs 8 pounds and Goliath weighs 80 pounds. How much will your total cost be if you get all three dogs groomed?

1 answer:

meriva3 years ago

6 0

Answer:

$170

Step-by-step explanation:

Sally costs 30

Max costs 40

Goliath costs 80(1.25) = 100

add them up

$170

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What are the factors to 424,380

Alona [7]

Answer:

the factors are: 1, 2, 3, 4, 5, 6, 10, 11, 12, 15, 20, 22, 30, 33, 44, 55, 60, 66, 110, 132, 165, 220, 330, 643, 660, 1286, 1929, 2572, 3215, 3858, 6430, 7073, 7716, 9645, 12860, 14146, 19290, 21219, 28292, 35365, 38580, 42438, 70730, 84876, 106095, 141460, 212190, 424380.

Step-by-step explanation:

4 0

3 years ago

What is the equation of the circle if the center is (-4,10) and radius of 7

natulia [17]

The answer will be -2

8 0

3 years ago

Read 2 more answers

Find the height of a right cylinder with surface area 160pie square units and radius 5 units

jenyasd209 [6]

Given:

Radius of a cylinder = 5 units.

Surface area of the cylinder = $160\pi$

To find:

The height of the right cylinder.

Solution:

Surface area of a cylinder is:

$A=2\pi rh+2\pi r^2$

Where, r is radius and h is the height of the cylinder.

Putting $r=5, A=160\pi$ in the above formula, we get

$160\pi =2\pi (5)(h)+2\pi (5)^2$

$160\pi =10\pi h+2\pi (25)$

$160\pi =10\pi h+50\pi$

Subtract $50\pi$ from both sides.

$160\pi -50\pi=10\pi h$

$110\pi=10\pi h$

Divide both sides by $10\pi$ .

$\dfrac{110\pi}{10\pi}=h$

$11=h$

Therefore, the height of the cylinder is 11 units.

8 0

3 years ago

1) A TV is on sale for 20% off. If the sale price is $700, what is the original

barxatty [35]

Answer:

140

Step-by-step explanation:

20% of 700

so 20/100 * 700

20*7

140

4 0

3 years ago

◆ Quadratic Equations ◆<br>Please help !

Mila [183]

I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.

Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:

a = 1
b = 2
c = 3
d = 4

$\sf ax^2+(1-a(b+c))x+abc-d)$

$\sf 1x^2+(1-1(2+3))x+(1)(2)(3)-(4))$

Simplify into standard form:

$\sf x^2+(1-1(5))x+6-4$

$\sf x^2+(1-5)x+2$

$\sf x^2-4x+2$

Use the quadratic formula to solve:

$\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

For functions in the form of $\sf ax^2+bx+c$ . So in this case:

a = 1
b = -4
c = 2

Plug them in:

$\sf x=\dfrac{4\pm\sqrt{(-4)^2-4(1)(2)}}{2(1)}$

Solve for 'x':

$\sf x=\dfrac{4\pm\sqrt{16-8}}{2}$

$\sf x=\dfrac{4\pm\sqrt{8}}{2}$

$\sf x\approx\dfrac{4\pm 2.83}{2}$

$\sf x\approx 0.59,3.41$

So the answer would be A.

3 0

3 years ago