Answer:
Horizontal distance = 0 m and 6 m
Step-by-step explanation:
Height of a rider in a roller coaster has been defined by the equation,
y = 
Here x = rider's horizontal distance from the start of the ride
i). 

![=\frac{1}{3}[x^{2}-2(3x)+9-9+24]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B3%7D%5Bx%5E%7B2%7D-2%283x%29%2B9-9%2B24%5D)
![=\frac{1}{3}[(x^{2}-2(3x)+9)+15]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B3%7D%5B%28x%5E%7B2%7D-2%283x%29%2B9%29%2B15%5D)
![=\frac{1}{3}[(x-3)^2+15]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B3%7D%5B%28x-3%29%5E2%2B15%5D)

ii). Since, the parabolic graph for the given equation opens upwards,
Vertex of the parabola will be the lowest point of the rider on the roller coaster.
From the equation,
Vertex → (3, 5)
Therefore, minimum height of the rider will be the y-coordinate of the vertex.
Minimum height of the rider = 5 m
iii). If h = 8 m,


(x - 3)² = 9
x = 3 ± 3
x = 0, 6 m
Therefore, at 8 m height of the roller coaster, horizontal distance of the rider will be x = 0 and 6 m
Answer:
A. the difference of two squares
Step-by-step explanation:
Please use the symbol " ^ " to indicate exponentiation.
Then we have x^2 - 11^2, which is the difference of two squares:
x^2 is a square, the square of x; and 11^2 is a square, the square of 11.
A. the difference of two squares
Note that a "difference of squares" is easily factored:
a² - b² = (a - b)(a + b)
and so your x² - 11² factors as follows: (x - 11)(x + 11)
s = 2(lw + lh + wh)
Divide each side by 2 : s/2 = lw + lh + wh
Subtract 'lh' from each side: s/2 - lh = lw + wh
Combine the 'w' terms: s/2 - lh = w(l + h)
Divide each side by (l + h): (s/2 - lh) / (l + h) = w
Answer: 7°
Explanation:
FBD = EBC
2x + 3 = 9x - 11
-7x = -14
x = -14/-7
x = 2
EBC = 9(2) - 11 = 18 - 11 = 7°
Answer:
Option (2)
Step-by-step explanation:
Given:
AC is an angle bisector of ∠DAB and ∠DAB
m∠BCA ≅ m∠DCA
m∠BAC ≅ m∠DAC
To Prove:
ΔABC ≅ ΔADC
Solution:
Statements Reasons
1). m∠BCA ≅ m∠DCA 1). Given
2). m∠BAC ≅ m∠DAC 2). Given
3). AC ≅ AC 3). Reflexive property
4). ΔABC ≅ ΔADC 4). ASA property of congruence
Therefore, Option (2) will be the correct option.