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4 years ago

What is the slope of a line that is perpendicular to 4x-8y=64

Mathematics

1 answer:

aleksley [76]4 years ago

4 0

Answer:

- 2

Step-by-step explanation:

1) Write the equation in slope-intercept form.

4x - 8y = 64

-8y = -4x +64

y = 1/2 x - 8

slope of this line = 1/2

2) For perpendicular line the slope is negative reciprocal.

So, slope for perpendicular line is equal -2.

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3 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

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$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

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$|CD|=\sqrt{16+4}$

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Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

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