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Murrr4er [49]
3 years ago
10

15 POINTS! someone pls answer

Mathematics
1 answer:
Lapatulllka [165]3 years ago
4 0

Surface Area, eh?

So, to solve this, you need to understand that Surface Area is just the added areas of the faces that make up the figure!

So, we just find all the areas of the faces, add them together, and there you go!

Let's solve!

SA=(14*10)+2(25*10)+2(\frac{24*14}{2})

So, there is our equation!

Wondering how I got it? Follow along!

I got (14*10) with that rectangle on the end of that rectangular prism, simple, as the area is just the multiplication of the lengths of the sides.

Now, same thing with 2(25*10), but why did I multiply by 2? It is because there is an identical face on the other side.

I also got 2(24*14/2) with the area of a triangle formula as the altitude is 24m. if you don't know what that is, might want to check google!(I also multiplied it by 2 because there was another identical face on the other side).

So, now that you understand where I am coming from, let us solve!

SA=140+500+336\\SA=976

More accurately, it is 976 m^2!

So, there you have it!

If you do need more help, check online! It is the greatest source of information that we have developed!

Adios!

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In slope-intercept form find a line that passes through (-4, 6) and is perpendicular to 2x + 3y = 12
leonid [27]

Answer:

y = 3/2 * x + 12

Step-by-step explanati

2x + 3y = 12

y = -2/3x + 4

slope: -2/3

slope' of perpendicular line: 3/2

6 = 3/2 * (-4) + b

b = 12

equation: y = 3/2 * x + 12

8 0
3 years ago
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Mamont248 [21]

Answer:

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8 0
3 years ago
What two number multiply to get negative 18
densk [106]
6 and -3 which is -18
3 0
4 years ago
Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
Find the area of a circle that has a diameter of 11 inches. Approximate Π as 3.14. Round your answer to the nearest hundredth.
Alexus [3.1K]

Answer: 94.99 in^2

Step-by-step explanation: The equation for the area of a circle is A=πr^2. To solve this, we need to find the radius. The diameter is the whole circle, whole the radius is half. So divide the diameter by 2.

11/2 = 5.5

The radius is 5.5 inches. Plug the radius into the equation.

A=π5.5^2

Square the 5.5 first. You will get 30.25.

A=π30.25

Plug in 3.14 for pi.

A=3.14 x 30.25

Multiply.

A=94.985

Round to the nearest hundredth.

A=94.99

The area of the circle is 94.99 in^2.

7 0
4 years ago
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