see the attached figure to better understand the problem
we know that
1) If angle 1 and angle 2 are complementary angles
then
m∠1+m∠2=
------> equation A
2) If angle 1 and angle 2 are congruent angles
then
m∠1=m∠2 ------> equation B
Substitute equation B in equation A
m∠1+(m∠1)=
2m∠1=
m∠1=
therefore
<u>the answer is</u>
Answer:
The answer is 5/8
Step-by-step explanation:
Step 1 : Convert both fractions so they have the same denominator (bottom number in the fraction.)
1/4 = 2/8
So now were dealing with :
2/8 + 3/8 = ?
Step 2 : Add the numerators together to get the numerator for our answer.
2 + 3 = 5
When adding two fractions with the same denominator the denominator stays the same, so our answer is 5/8.
Hope this helps, please mark brainliest. :) Have a nice day.
First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is:
delta x= (v)(t) -0.5(acceleration)(time)^2
delta x= 29.4 times (3) - 0.5 (9.8) times 9
delta x= 44.1
100 minus 44.1 equals 55.9, which is the answer for part a.
Tell me if you need any clarification
PART B:
The kinematic equation for this is:
delta x= (initial velocity) times time plus 0.5 (a)(time)^2
100=(0)times(x) plus 0.5 (a)(time)^2
100=0.5(9.8)(x)^2
100=4.9x^2
100/4.9 is approxamitely 20.4.
The squareroot of this is approxamitely 4.5.
4.5 seconds
Tell me if you need any clarification
Answer:
90 cents
Step-by-step explanation:
Find how much money you have by plugging in 18 as n into the expression:
5n
5(18)
Multiply:
= 90
So, when you have 18 nickels, you have 90 cents
Answer:
Step-by-step explanation:
A vector perpendicular to the plane ax+by+cz+d=0 is of the form 
.
So, a vector perpendicular to the plane x − y + 2z = 7 is 
.
The parametric equations of a line through the point 
and parallel to the vector are as follows:
Put 
and 
Therefore,
xy-plane:
Put z = 0 ⇒ t = -2 ⇒x = - 1 , y = 6
So, at point (-1,6,0)
yz-plane:
Put x = 0 ⇒ t = -1 ⇒ y = 5, z =2
So, at point (0,5,2)
xz-plane:
Put y = 0 ⇒ t = 4 ⇒ x = 5, z = 12
So, at point (5,0,12)
