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velikii [3]
2 years ago
14

It’s really urgent if you’re not sure please don’t answer I tried solving it like thousands of times. I need the answer to #3

Mathematics
1 answer:
mr Goodwill [35]2 years ago
5 0
Ok so how you do it is on the left nearest to the example number line the compound equality would be x then “<“ this sign with the line under it, then “-3”. For the right side you would put “x > 2” respond if you have any questions
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10.Which of the following values does not satisfy the inequality ?
kupik [55]

Answer:

The answer is -4

Step-by-step explanation:

-2x-6<=1

-2(-4)-6<=1

8-6<=1

2<=1 which is False

-2x-6<=1

-2(-3)-6<=1

6-6<=1

0<=1 which is True

-2x-6<=1

-2(-2)-6<=1

4-6<=1

-2<=1 which is True

-2x-6<=1

-2(-1)-6<=1

2-6<=1

-4<=1 which is True

7 0
2 years ago
A container has peppermint gum and spearmint gum. There are 32 pieces of peppermint gum in the container and the ratio of pepper
lapo4ka [179]
I think the answer is 28 prices of spearmint gum because 32/8=4 so if you multiply 7*4 you get 28??????

Hope this helped!!! Sorry if I’m wrong.
7 0
2 years ago
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Express the sum of 0.041 and 0.004 as a fraction in its simplest form
Vedmedyk [2.9K]
0.041 + 0.004
= 0.045
= 45/1000
8 0
2 years ago
Gus makes 48 fluid ounces of spiced cider. If he serves an equal amount to each of 7 people, will each person get more than I cu
Anni [7]

Answer:

Each person get less than 1 cup of cider.

Step-by-step explanation:

1. Calculate the amount of cider served to each person:

Total amount of cider is 48 fluid ounces

Gus serves 7 people

Let Q the amouunt of cider served to each person:

Q=\frac{48}{7}=6.85

Then, each person recived 6.85 fluid ounces of spiced cider.

2. Calculate the number of cups served:

Considering that 1 cup=8 fluid ounces, then:

Q=6.85\frac{1}{8}=0.85

That means that each person recived 0.85 cups of spiced cider.

Each person get less than 1 cup of cider.

4 0
3 years ago
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Find the minimum value of
vekshin1

Step-by-step explanation:

C=y[20]

Cy=[20] Answer is Cy=[20]

3 0
2 years ago
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