Step-by-step explanation:
Given :-
The length of the garden 8m greater than 2 times the width.
Area of the garden is 280 m²
Let us consider the length as x and width as y.
Sp, we can day length as :-
x = 8 + 2y ---(1)
Now, we know that:-
Area of Rectangle = Length × Breadth
280 = x * y
We can replace the value of x now,
280 = y × ( 8 + 2y)
280 = 8y + 2y²
2y² + 8y - 280 = 0
y² + 4y - 140 = 0
Factorise it.
(y -10)(y + 14)
Cancelling -ve value, we get the width as 10 metres.
<u>Hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>:</u><u>)</u>
Answer:
The change in the area of the rectangle is 0 square feet
Step-by-step explanation:
To solve this problem we have to calculate the area of the two rectangles that give us
first we have to know the formula to calculate the area of a rectangle
a = area
l = length = 12ft
w = width = 5ft
a = l * w
we replace the known walues
a = 12ft * 5ft
a = 60ft²
we do the same with the other rectangle, but first we have to calculate its sides
w = 5ft - (5ft * 20/100)
w = 5ft - 1ft
w = 4ft
l = 12ft + (12ft * 25/100)
l = 12ft + 3ft
l = 15ft
a2 = 15ft * 4ft
a2 = 60ft²
to calculate the change in the area we subtract (a - a2)
a - a2 =
60ft² - 60ft² = 0ft²
Answer:
(-1,1,3)
Step-by-step explanation:
midpoint = (x1+x2/2, y1+y2/2, z1+z2/2)
midpoint = ( (-6+4)/2, (3+-1)/2, (4+2)/2 )
midpoint = (-2/2, 2/2, 6/2)
midpoint = (-1, 1, 3)
Answer:
Step-by-step explanation:
Cross multiply and get:
L = 5w
L = 5w/
W = L/5
