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2 years ago

PLZ answer my question for God's sake

Mathematics

1 answer:

timofeeve [1]2 years ago

4 0

Answer:

a. 2x+3z

b. 7xy

c. $\frac{3ab}{2c}$

d. 10z-6q

e. Subtract xy from the sum of p and q.

f. Divide the sum of 3 and y by 5.

g. Subtract 2c from the square root of b.

h. 3x ... 4x ...

i. 3y ... y+5 ... 5y+5

j. length ... 3 ... breadth ... 8b ... 3b²

Step-by-step explanation:

Sum means addition. 2x + 3z

Product means multiplication. 7y × x = 7xy

Divide 3ab by 2c. 3ab ÷ 2c = $\frac{3ab}{2c}$

Subtract 6q from 10z. 10z-6q

(p+q)-xy : Subtract xy from the sum of p and q.

(3+y)/5: Divide the sum of 3 and y by 5.

$\sqrt{b}$ - 2c: Subtract 2c from the square root of b.

Let the number of boys be x. Girls are three times more so 3 × x = 3x. The total would be 3x + x = 4x.

Let Nora's age be y. Father is three times more so 3 × y = 3y. Brother is 5 more so would be y+5. The total would be y + 3y + y + 5 = 5y+5

3b is three times more than b, the breadth. Thus, the length is three times more than the breadth since it is 3b. The perimeter would be 3b + b + 3b + b = 8b. The area would be 3b × b = 3b²

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The first term of your first series is 3 so your answer will be given by:

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2 years ago

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2 years ago

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---------------------

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3 years ago

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3 years ago

PLZ answer my question for God's sake​

PLZ answer my question for God's sake