PLZ answer my question for God's sake
1 answer:
Answer:
a. 2x+3z
b. 7xy
c.
d. 10z-6q
e. Subtract xy from the sum of p and q.
f. Divide the sum of 3 and y by 5.
g. Subtract 2c from the square root of b.
h. 3x ... 4x ...
i. 3y ... y+5 ... 5y+5
j. length ... 3 ... breadth ... 8b ... 3b²
Step-by-step explanation:
Sum means addition. 2x + 3z
Product means multiplication. 7y × x = 7xy
Divide 3ab by 2c. 3ab ÷ 2c =
Subtract 6q from 10z. 10z-6q
(p+q)-xy : Subtract xy from the sum of p and q.
(3+y)/5: Divide the sum of 3 and y by 5.
- 2c: Subtract 2c from the square root of b.
Let the number of boys be x. Girls are three times more so 3 × x = 3x. The total would be 3x + x = 4x.
Let Nora's age be y. Father is three times more so 3 × y = 3y. Brother is 5 more so would be y+5. The total would be y + 3y + y + 5 = 5y+5
3b is three times more than b, the breadth. Thus, the length is three times more than the breadth since it is 3b. The perimeter would be 3b + b + 3b + b = 8b. The area would be 3b × b = 3b²
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Step-by-step explanation:
Using R, I used the following code to create a histogram:
bowling.scores <- c(87, 104, 79, 94, 117, 82, 72, 116, 105, 95, 88, 93, 109, 119, 75,
103, 112, 97, 73, 85, 91, 86, 102, 99, 106, 84, 98, 83, 81, 96, 92)
data.frame(bowling.scores)
ggplot(data.frame(bowling.scores), aes(x=bowling.scores)) +
xlim(c(70, 120)) +
scale_y_continuous(breaks = seq(0, 10, by=1), "Frequency") +
geom_histogram(breaks=seq(70, 120, by=10), color="black", fill="grey60") +
labs(title="Histogram of Bowling Scores", x="Bowling Scores", y="Frequency")
Answer:
{-11, -9, -7, -5, -3}
Step-by-step explanation:
Put each domain value into the function to find the corresponding range value. The range is the list of all of those values.
__
range = f(domain)
= 2{-2, -1, 0, 1, 2} -7 = {-4, -2, 0, 2, 4} -7
= {-11, -9, -7, -5, -3} . . . . . the range for the given domain
_____
If you have a lot of function values to find, a spreadsheet or calculator can be helpful.
