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-Dominant- [34]
3 years ago
14

40, 90, 36, 68, 90, 11, 88, 54 What is the mean,median,mode, and range? Thanks m8!

Mathematics
2 answers:
sashaice [31]3 years ago
7 0

Answer:

mean 59.625

median 61

mode 90

range 79

Step-by-step explanation:

dimaraw [331]3 years ago
3 0

Answer:

Step-by-step explanation:

The mean is 59.625 because if you add all of the listed numbers together and then divide by how many numbers are listed (8) you get a mean of 59.625.

The median is 61 because you first list the numbers from least to greatest, then you see what number(s) are in the middle. Last, since there would be two (54 and 68) you then divide by 2 to get the median of 61.

The mode is 90, because it appeared two times in the list of numbers.

Last, the range is 79 because first you would list the numbers from least to greatest, then you take the lowest and higher numbers and subtract them from each other, which would be 79.

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4 0
4 years ago
State the domain of the relation.
gogolik [260]

Answer:

The Domain of the relationship is the set: {-3, -2, -1, 0, 1, 2} (Answer B)

Step-by-step explanation:

Let's recall that the Domain of a relationship is the set of values in the starting set for which there is a correspondent value in the final set.

In this case, we have a set of numbers on the x axis, which are connected with values in the y axis as indicated by the plotting of the points on the (x,y) plane.

The Domain will consist of all those x-values for which we see in the given plot connected to a corresponding y-value.

So, we see that:

the x-value -3 is connected to the y-value -4

the x-value -2 is connected to the y-value -3

the x-value -1 is connected to the y-value -1

the x-value 0 is connected to the y-value 0

the x-value 1 is connected to the y-value 3

and the x-value 2 is connected to two y-values:  4 and 5

Therefore all those x-values are part of the Domain of this relationship. That is, the set: {-3, -2, -1, 0, 1, 2}

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4 years ago
What's the greatest common factor of 5x^2+3x
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4 years ago
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What is the lowest whole number for hypotenuse c when using the formula <img src="https://tex.z-dn.net/?f=%5Csqrt%7Ba%5E2%2Bb%5E
nata0808 [166]

9514 1404 393

Answer:

  0

Step-by-step explanation:

If a=b, you are asking for a whole number c such that ...

  c = √(a² +a²) = a√2

If 'a' is a whole number, the only whole numbers that satisfy this equation are ...

  c = 0 and a = 0.

  0 = 0×√2

The lowest whole number c such that c = √(a²+b²) and a=b=whole number is zero.

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√2 is irrational, so there cannot be two non-zero whole numbers such that c/a=√2.

_____

<em>Additional comment</em>

If you allow 'a' to be irrational, then you can choose any value of 'c' that you like. Whole numbers begin at 0, so 0 is the lowest possible value of 'c'. If you don't like that one, you can choose c=1, which makes a=(√2)/2 ≈ 0.707, an irrational number. The problem statement here puts no restrictions on the values of 'a' and 'b'.

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3 years ago
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