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3 years ago

Target Product: 96 Target Sum: -35 The 2 factors are 32 & 3 O True O False

Mathematics

2 answers:

4vir4ik [10]3 years ago

7 0

Answer:

False

Step-by-step explanation:

The two factors must be negative to result in the negative sum of -35 when added.

-Dominant- [34]3 years ago

3 0

The two factors of -35 is not 32 and 3

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What expression represents '' five times the quotient of some number and ten"? A.5(z/10) B.5(z-10) C.5(10/z) D.5(10-z)

maw [93]

Answer:

Option A is correct

$5(\frac{z}{10})$

Step-by-step explanation:

Let the number be z.

Given the statement:

'' five times the quotient of some number and ten"

" quotient of some number and ten" translated to $\frac{z}{10}$

"five times the quotient of some number and ten" translated to $5 \times \frac{z}{10}$

Then, the expression we get,

$5(\frac{z}{10})$

Therefore, $5(\frac{z}{10})$ expression represents '' five times the quotient of some number and ten"

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3 years ago

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miss Avery is going to bring the select one student from your class to read a poem out loud. There are 15 boys and 13 girls in t

tester [92]

There are 15 boys what are you asking the sentence is not complete

4 0

3 years ago

Solve using elimination x-2y=12 and 5x+3y=-44 (4,8) (-4,8) (4,-8) (-4,-8)

Leya [2.2K]

Answer:

(-4, -8)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

x - 2y = 12

5x + 3y = -44

Step 2: Rewrite Systems

x - 2y = 12

[Multiplication Property of Equality] Multiply everything by -5: -5x + 10y = -60

Step 3: Redefine Systems

-5x + 10y = -60

5x + 3y = -44

Step 4: Solve for y

Elimination

Combine 2 equations: 13y = -104
[Division Property of Equality] Divide 13 on both sides: y = -8

Step 5: Solve for x

Define original equation: x - 2y = 12
Substitute in y: x - 2(-8) = 12
Multiply: x + 16 = 12
[Subtraction Property of Equality] Subtract 16 on both sides: x = -4

6 0

3 years ago

In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.

WARRIOR [948]

Answer:

For First Solution: $y_1(t)=e^t$

$y_1(t)=e^t$ is the solution of equation y''-y=0.

For 2nd Solution: $y_2(t)=cosht$

$y_2(t)=cosht$ is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: $y_1(t)=e^t$

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

$y_1(t)=e^t$

First order derivative:

$y'_1(t)=e^t$

2nd order Derivative:

$y''_1(t)=e^t$

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence $y_1(t)=e^t$ is the solution of equation y''-y=0.

For 2nd Solution:

$y_2(t)=cosht$

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

$y_2(t)=cosht$

First order derivative:

$y'_2(t)=sinht$

2nd order Derivative:

$y''_2(t)=cosht$

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence $y_2(t)=cosht$ is the solution of equation y''-y=0.

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3 years ago

Solve for k, f=1/2kp

iVinArrow [24]

Hope this helps! Answer: k = 2f/p

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3 years ago