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aivan3 [116]
3 years ago
8

Can someone help me with 1-142 all the way to 1-144??

Mathematics
1 answer:
mezya [45]3 years ago
5 0

CL.1.142):

A):      

x5 ==>      4 boxes  =   3ft   <==== x5

20 boxes   =       ?  ft

20 boxes  is    15 ft. high



B):   x3  ===>   4 boxes     =    3ft.  <==== x3

   ?   boxes           =          9ft.

       12 boxes  will fit in one stack.



c):  CL.143

 Perimeter  =     15  +  29  +  9  +  11  +  6  +  18   =====>  88m

A1    =    b  *   h

(18)(15)  

270m^2


A2    =   b  *  h

(11)(9)

99

Total  Area ======>   270    +    99   ======>  369m^2









CL.1-144

1/4    +   1/4   +   1/5     =    5/20    +   5/20   +   4/20    ====>    14/20

1/4  *    5/5  =====>  5/20

1/5   *    4/4    =====>  4/20

14/20      +      ?/20       =      20/20

?      =       6  Missing    Section

6/20      ======>     3/10





CL-1.145

A):   40/100       =     4/10   ====>   2/5

0.4            ========>    40%



B):    1/6  ======>   .00000

0.16 (Repeating 6)  ======>  16.6%



C):   37.5/100     =    375/1000     =======>     3/8

0.375      =========>   37.5%





CL-1.146

ADD:   1/6   +   1/2   show all steps:

1/6   +   1/2

1/6    +    3/6

1   +   3 / 6

4/6  =======>    2/3     =======>   Decimal:   =======>   0.666667






Hope that helps!!!!                                   : )


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Lubov Fominskaja [6]

Answer:

M = 5742π  

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

                             ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

                             0 ≤ z ≤ 81 - r^2

                             0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

                           M = \int \int \int {p ( r ,theta, z)} \, dV\\\\

- We can write the above expression in cylindrical coordinates:

                           M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\

- Perform integration:

                           M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\

                           M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] }  \, dtheta\\\\M = 5742\pi  kg              

- The mass evaluated is M = 5742π                      

8 0
3 years ago
How does the Binomial Theorem’s use Pascal’s triangle to expand binomials raised to positive integer powers?
MrMuchimi

Answer:

There are  ways for quickly multiply out a binomial that's being raised by an exponent. Like

(a + b)0 = 1

(a + b)1 = a + b

(a + b)2 = a2 + 2ab + b2

(a + b)3 = (a + b)(a + b)2 = (a + b)(a2 + 2ab + b2) = a3 + 3a2b + 3ab2 + b3

and so on and so on

but there was this mathematician named Blaise Pascal and he found a numerical pattern, called Pascal's Triangle, for quickly expanding a binomial like the ones from earlier. It looks like this

1                           1      

2                   1     2     1

3                1     3     3   1

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5       1     5     10     10     5     1

Pascal's Triangle gives us the coefficients for an expanded binomial of the form (a + b)n, where n is the row of the triangle.

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Mindy and Troy combined ate 9 99 pieces of the wedding cake. Mindy ate 3 33 pieces of cake and Troy had 1 4 4 1 ​ start fraction
saul85 [17]

Answer:

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(b)There are 15 pieces of cakes left

Step-by-step explanation:

Let the total cakes=x

Let number of cakes eaten by Mindy=m

Let number of cakes eaten by Troy=t

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m=3

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3+t=9

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Since Troy had \frac{1}{4} of the total cake

\frac{1}{4} of x=6

\frac{1}{4} X x=6

x=6X4=24

(a)There are 24 cakes in total

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Label the quadrants IV​
nevsk [136]

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Quadrant IV is always in the bottom right corner.

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