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garik1379 [7]
3 years ago
13

Tristen's cat had 3 baby kittens. Each kitten weighed 1 pounds. How many ounces did all of his kittens weigh together?​

Mathematics
1 answer:
Tema [17]3 years ago
5 0
3 times 1. 3 pounds in all
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HELP ASAP PLEASE
Verizon [17]

Answer:

  • 1.25 g

Step-by-step explanation:

<u>Given:</u>

  • Initial mass is m = 80 g.
  • Half life = 10 days
  • Total time = 60 days

<u>Number of half-life periods:</u>

  • r = 60/10 = 6

<u>Equation for remaining sample:</u>

  • s = m*(1/2)^r
  • s = 80*(1/2)^6 = 80/64 = 1.25 g
5 0
2 years ago
At a physics convention, 10 companies set up equal sized square booths in a row along one wall of the convention center. The boo
exis [7]
I'm not 100% sure what this all means because I'm in a different school but, I believe they have a side length of 4600.


P.S. If it doesn't work, I am so sorry
3 0
3 years ago
15 less than quadruple a number w​
vichka [17]

Answer:

4w-15

Step-by-step explanation:

For expressions that have "more than/less than" , that number goes AFTER the "whatever a number" statement because that's just how they explain it. I don't remember the exact reason why, but that is how my professor made me remember it, and yes, the order WILL affect the expression since that's a specific topic and I suppose you're being tested on how to make algebraic expressions based on descriptions.

8 0
2 years ago
PYTHAGORAS THEROM AND TRIGONOMETRY RATIO​
marysya [2.9K]

Answer:

1) ΔACD is a right triangle at C

=> sin 32° = AC/15

⇔ AC = sin 32°.15 ≈ 7.9 (cm)

2) ΔABC is a right triangle at C, using Pythagoras theorem, we have:

AB² = AC² + BC²

⇔ AB² = 7.9² + 9.7² = 156.5

⇒ AB = 12.5 (cm)

3)  ΔABC is a right triangle at C

=> sin ∠BAC = BC/AB

⇔ sin ∠BAC = 9.7/12.5 = 0.776

⇒ ∠BAC ≈ 50.9°

4) ΔACD is a right triangle at C

=> cos 32° = CD/15

⇔ CD = cos32°.15

⇒ CD ≈ 12.72 (cm)

Step-by-step explanation:

7 0
3 years ago
Can you help me? Please
Anni [7]

9514 1404 393

Answer:

  a.

Step-by-step explanation:

For an even-index radical, ...

  \sqrt[n]{x^n}=|x|\qquad\text{n even}

This lets us simplify the given expression as follows:

  \sqrt[4]{81x^6y^4}-|y|\sqrt[4]{x^6}-\sqrt[4]{16x^2}=\sqrt[4]{(3xy)^4x^2}-|y|\sqrt[4]{x^4x^2}-\sqrt[4]{2^4x^2}\\\\=3|xy|\sqrt[4]{x^2}-|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}=\boxed{2|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}}

4 0
2 years ago
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