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Diano4ka-milaya [45]
3 years ago
15

What is the measure of Zx?

Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0

Answer:

<h2>∠x = 74°</h2><h2 />

Step-by-step explanation:

wxz = wxy + yxz

180 = x + 106

x = 180 - 106

x = 74°

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I've included two questions. Hopefully you can help me with both. Thanks!
lubasha [3.4K]

Answer:

  1.  value is 0; x-3 is a factor . . . . . . . . . . . . . .third choice

  2.  evaluates at x = -1; remainder is -11 . . . . first choice

Step-by-step explanation:

Dividing f(x) by (x -a) gives ...

  f(x)/(x -a) = g(x) +r/(x -a) . . . . some quotient and a remainder r

If we multiply this expression by (x -a), we see ...

  f(x) = (x -a)g(x) +r

so

  f(a) = (a -a)g(a) +r . . . . . evaluate the above equation at x=a

  f(a) = 0 +r

  f(a) = r . . . . . . . . . a statement of the remainder theorem

If r=0, then x-a is a factor of f(x) = (x-a)g(x).

___

1. We have "a" = 3, and f(3) = 0. Therefore (x-3) is a factor.

__

2. We have "a" = -1, and f(-1) = -11. Therefore the remainder from division by (x+1) is -11.

6 0
3 years ago
Need help with my final it’s my final grade
WARRIOR [948]
Its D because supplementary means equal to 180 so 151+29 is 180 there its D
6 0
3 years ago
JL is a diameter of circle k. If tangents to circle I are constructed through points L and K what relationships would exist betw
luda_lava [24]

i. Let t be the line tangent at point J. We know that a tangent line at a  point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the 
3 0
3 years ago
Evaluate the expression (2.5)^3
sergejj [24]

Answer:

15.625

Step-by-step explanation:

  • (2.5)^3 = 2.5 · 2.5 · 2.5
  • 2.5 · 2.5 · 2.5 = 6.25 · 2.5
  • 6.25 · 2.5 = 15.625

Therefore, (2.5)^3 = 15.625.

7 0
2 years ago
Read 2 more answers
How many ways can a dance instructor send 4 of her 11 students to a summer dance program?
Sedaia [141]

Answer:

d) 330

Step-by-step explanation:

The number of ways can a dance instructor send 4 of her 11 students to summer dance program is  C(11 , 4)

That is 11_{C_{4} } ways

by using formula n_{C_{r} } = \frac{n!}{(n-r)!r!}

now simplification

11_{C_{4} } = \frac{11!}{(11-4)!4!}

      = \frac{11X10X9X8X7!}{(7!)4X3X2X1}

after cancelling 7! and on simplification

   = \frac{11X10X9X8}{4X3X2X1}

after cancellation we get 330 ways

The number of ways can a dance instructor send 4 of her 11 students to summer dance program is 330

   

8 0
3 years ago
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