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2 years ago

Please help me!!!!!!

Mathematics

2 answers:

aev [14]2 years ago

8 0

- 10, you go down 4 - this is shown because to get from two to 10 in two, you have to go 2+4=6+4=10

QveST [7]2 years ago

8 0

-10, because it’s going down in four

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Hi pls help answer this!

Morgarella [4.7K]

Answer:

363-138=-5x

Step-by-step explanation:

Let c = cost

We know that the total cost is $363:

363-??????

We also know that he spent $138 on parts:

363-138?????

And we are solving for the cost of labor per hour:

363-138=5x

We can use this equation to find the total cost of labor per hour.

Hence, your equation will be 363-138=5x

7 0

2 years ago

45 cm 60 om What is the length of the hypotenuse? centimeters?

ExtremeBDS [4]

Answer:

Answer:

Length of leg of triangle =

Step-by-step explanation:

We are given a 45°-45°-90° triangle with hypotenuse measuring 18 cm.

Let us assume the following labeling of the diagram, as attached in the answer area.

The two angles here are equal to 45° so two sides of the triangle opposite to the equal angles will also be equal to each other i.e. it is an isosceles triangle.

i.e. The sides XY and YZ will be equal.

Let XY = YZ = x cm

It is known that in a right angled triangle, pythagorean theorem holds well.

As per pythagoream theorem:

Putting the values:

So, the length of leg of triangle =

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

PLEASE ANSWER + BRAINLIEST!! Factor completely. 4k - 20k^9 = 3b^2 - 108 =

Neporo4naja [7]

$4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)$

$3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)$

$Used:\ (a-b)(a+b)=a^2-b^2$

7 0

3 years ago

Mixed numbers greater than 6 but less than 7 use an interval of 1/6 between each pair of numbers

GaryK [48]

Answer:

$[6\frac{1}{6},6\frac{1}{3},6\frac{1}{2},6\frac{2}{3},6\frac{5}{6}]$