Answer:
<em>(2x-y+2)(2x+y-2)</em>
Step-by-step explanation:
4x² - y² + 4y - 4=
=(2x)²-(y²-4y+4)
=(2x)²-(y-2)²
= [2x-(y-2)][2x+(y-2)]
<em>=(2x-y+2)(2x+y-2)</em>
a²-b²=(a-b)(a+b)
St ÷ 6r
(32)(45) ÷ 6(5)
1440 ÷ 30
48
Step-by-step explanation:
Answer:
The inequality in this case is 100 + 400*t > 500 + 350*t and for B to be cheaper Sophia has to rent it for more than 8 months.
Step-by-step explanation:
In order to write the inequality we first need to write two equations one for each apartment. For apartment A we have a fixed cost of $100 and a variable cost of $400 that varies according to the time living in there, so we have:
rent = 100 + 400*t
For apartment B we have a fixed cost of $500 and a variable cost of $350 that varies according to the time living in there, so we have:
rent = 500 + 350*t
In order for the total paid in B to be less than for the one in A we need to satisfy the following inequality:
100 + 400*t > 500 + 350*t
400*t - 350*t > 500 - 100
50*t > 400
t > 400/50
t > 8 months
The inequality in this case is 100 + 400*t > 500 + 350*t and for B to be cheaper Sophia has to rent it for more than 8 months.
a is the fifth term of a sequence. It represents the value of a depreciating
5 asset (your car) after 5 years have gone by since its purchase.
24,000 (really, $24,000) represents the initial value of the car.
(3/4) is the common ratio. Since (3/4) is between 0 and 1, we know the car is depreciating (losing value) each year, and that the value of the car at the end of this year is (3/4) times the previous value.
