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sweet [91]
3 years ago
15

-2j =-90 Answer: j = ? Answer the ? Mark pls

Mathematics
2 answers:
sleet_krkn [62]3 years ago
8 0

Answer:

j = 45

Step-by-step explanation:

-2j =-90

Divide each side by -2

-2j/-2 = -90/-2

j = 45

Nonamiya [84]3 years ago
5 0

Answer:

\huge\boxed{j=45}

Step-by-step explanation:

-2j=-90\qquad|\text{divide both sides by (-2)}\\\\\dfrac{-2j}{-2}=\dfrac{-90}{-2}\qquad|\text{we know}\ \dfrac{(-)}{(-)}\to(+)\\\\\dfrac{2\!\!\!\!\diagup j}{2\!\!\!\!\diagup}=\dfrac{90}{2}\\\\j=45

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The equation that's illustrated simply depicts an investment as it shows the principal, and interest rate.

<h3>What is an investment?</h3>

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3 years ago
Suppose that X is a subset of Y. Let p be the proposition ‘x is an element ofX’ and let q be the proposition ‘x is an element of
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Answer:

See answer below

Step-by-step explanation:

The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.

i) x∈AnB  if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB  then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.

ii) (I will abbreviate "if and only if" as "iff")

x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.

iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).

iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).

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its the first one

Step-by-step explanation:

because per pertains to to x

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