In a physics equation, given a constant acceleration (a, the change in
velocity of an object) and time involved (t), you can figure out the
distance (S) traveled by using this formula :
S = 1/2 x acceleration(a) x times(t)^2
So in this case, we can compute the distance by supplying the available data into the equation,...
S = 1/2 x 3.2 m/s2 x (32.8s)^2
S = 1721m
H is -24, -24/6=-4 so the H equals -24
Answer:
24
Step-by-step explanation:
Let's see the factor pairs of 60 first.
1,60
2,30
3,20
4,15
5,12
6,10
10,6
12,5
15,4
20,3
60,1
1,60 and 60,1 is not possible for xy1 and 1xy. It is because any one digit*one digit=not 60. The remaining pairs are...
2,30
3,20
4,15
5,12
6,10
10,6
12,5
15,4
20,3
30,2
Next, start with 2,30 and 30,2
The one digit factor pairs of 30 is 5 and 6.
So...
256 is possible
265 is possible
562 is possible
652 is possible
3,20
4,15
5,12
6,10
10,6
12,5
15,4
20,3
+4
Next, 3,20 and 20,3
20=4*5
453,543,345,354
4,15
5,12
6,10
10,6
12,5
15,4
+8
4,15 and 15,4
4 number that are possible(5*3=15)
5,12
6,10
10,6
12,5
+12
5,12 and 12,5
3,4 and 2,6
526,562,534,543,435,345,265,625
6,10
10,6
+20
10=5*2
+4
20+4=24
(Sorry it's long)
Answer:
Hope it helps
Step-by-step explanation:
A.)-8-5 X -8+6
-13 X -2
+26
B.)-3-8 = 2 X 4
-11≠8
please mark brainliest
Is it 2 times x squared (2x^2?
2 * 6^2
2 * 36
72
