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Tema [17]
3 years ago
14

HOW TO ROUND TO TWO DECIMAL PLACES ON THIS QUESTION?

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:

o.04

Step-by-step explanation:

3.141599/77= 0.04079987 to round to the second decimal point just go to the 3rd one, if the number is 5 or up the number goes one up, if its 4 down the number stays the same.

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If I live 16 minutes away from a movie theater and I need to be there at 5 what time do I leave​
TEA [102]

Answer:

4:44 so that you could be there at 5:00 exactly.

Step-by-step explanation:

6 0
3 years ago
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Which equation finds the length of side c of this right triangle
NeX [460]

Answer:

Find The Length Of The Side Of A Right Triangle : Example Question #1. Explanation: The Pythagorean Theorem gives us a2 + b2 = c2 for a right triangle, where c is the hypotenuse and a and b are the smaller sides.

Step-by-step explanation:

3 0
3 years ago
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Suppose a shoe factory produces both low-grade and high-grade shoes. The factory produces at least twice as many low-grade as hi
umka2103 [35]

Answer:

The factory should produce 166 pairs of high-grade shoes and 364 pairs of low-grade shoes for maximum profit

Step-by-step explanation:

The given parameters for the shoe production are;

The number of low grade shoes the factory produces ≥ 2 × The number of high-grade shoes produced by the factory

The maximum number of shoes the factory can produce = 500 pairs of shoes

The number of high-grade shoes the dealer calls for daily ≥ 100 pairs

The profit made per pair of high-grade shoed = Birr 2.00

The profit made per of low-grade shoes = Birr 1.00

Let 'H', represent the number of high grade shoes the factory produces and let 'L' represent he number of low-grade shoes the factory produces, we have;

L ≥ 2·H...(1)

L + H ≤ 500...(2)

H ≥ 100...(3)

Total profit, P = 2·H + L

From inequalities (1) and (2), we have;

3·H ≤ 500

H ≤ 500/3 ≈ 166

The maximum number of high-grade shoes that can be produced, H ≤ 166

Therefore, for maximum profit, the factory should produce the maximum number of high-grade shoe pairs, H = 166 pairs

The number of pairs of low grade shoes the factory should produce, L = 500 - 166 = 334 pairs

The maximum profit, P = 2 × 166 + 1 × 364 = 696

6 1
3 years ago
Read 2 more answers
Tickets for the baseball games were $2.50 for general admission and 50 cents for kids. If there were six times as many general a
Makovka662 [10]
There was 3000 general admission tickets sold and 500 kid ticket sold.

How did I get this?

First, we need to see what information we have.
$2.50 = General admission tickets = (G)
 $0.50 = kids tickets =  (K)
There were 6x as many general admission tickets sold as kids. G = 6K

We need two equations:
G = 6K  
$2.50G + $.50K = $7750
Since, G = 6K we can substitute that into the 2nd equation.

2.50(6K) + .50K = 7750
Distribute 2.50 into the parenthesis

15K + .50K = 7750
combine like terms

15.50K = 7750
Divide both sides by 15.50, the left side will cancel out.

K = 7750/15.50
K = 500 tickets
So, 500 kid tickets were sold.

Plug K into our first equation (G = 6k)

G = 6*500
G = 3000 tickets

So, 3000 general admission tickets were sold,

Let's check this:

$2.50(3000 tickets) = $7500 (cost of general admission tickets)
$.50(500 tickets) = $250 (cost of general admission tickets)
$7500 + $250 = $7750 (total cost of tickets)




4 0
3 years ago
Help !!!!!! Need to know ASAP
madreJ [45]

Answer:

Multiply by 5

5*2f-5*6g=10f-30g

5 0
3 years ago
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