Answer:
Equation is;
(D/8) + (D/4) = 1600
D = 4266.67 ft
Step-by-step explanation:
We are told that the bee flies at a rate of 8ft/sec directly to a flowerbed from its hive. Thus,
speed during this stage is; v1 = 8ft/sec
Time during this stage is; t1
The bee stays at the flower bed for 1200 seconds.
Thus, time at this stage is; t2 = 1200 s
It flies directly back to the hive at 4ft/sec.
Speed at this stage; v2 = 4 ft/s
Time at this stage; t3
We are told that it was away for a total of 2800 seconds.
Thus; t1 + t2 + t3 = 2800
Since t2 = 1200 s, then;
t1 + 1200 + t3 = 2800
t1 + t3 = 2800 - 1200
t1 + t3 = 1600
Now, during time t1, the speed was 8ft/sec, since distance is equal to speed × time, then we have;
D = 8t1
t1 = D/8
During time t3, the speed was 4ft/sec. Thus; D = 4t3
t3 = D/4
Thus,since t1 + t3 = 1600
Then;
(D/8) + (D/4) = 1600
Multiply through by 8 to get;
D + 2D = 1600 × 8
3D = 12800
D = 12800/3
D = 4266.67 ft
