Answer: Hello there!
A model to see the growth of a certain population is the exponential model.
If the initial population is P, then the model can be written as
![f(t) = Pe^{rt}](https://tex.z-dn.net/?f=f%28t%29%20%3D%20Pe%5E%7Brt%7D)
Where t is the time, and r is growth rate.
and f(0) = P
Then we want to know the time needed for the initial population to be doubled, this is f(x) = 2P, where x is the time that we want to find.
then ![f(x)=Pe^{rx} =2P](https://tex.z-dn.net/?f=f%28x%29%3DPe%5E%7Brx%7D%20%3D2P)
![e^{rx} = 2](https://tex.z-dn.net/?f=e%5E%7Brx%7D%20%3D%202)
![ln(e^{rx} ) = ln(2)](https://tex.z-dn.net/?f=ln%28e%5E%7Brx%7D%20%29%20%3D%20ln%282%29)
![rx = ln(2)](https://tex.z-dn.net/?f=rx%20%3D%20ln%282%29)
then x= ln(2)/r
Add all the numbers, then divide by how much numbers there is
Answer: 0.44mm
Step-by-step explanation:
In this problem we are asked for the height of a single playing chip. We know the volume of a cylinder is 25120 mm^3.
V=πr²h
25120=πr²h
The problem also gives the diameter of the case: 40mm.
To find radius, you divide the diameter in half.
d=2r
40=2r
r=20
With the radius, we can add that to the volume equation.
25120=
(20)^2h
25120=400πh
All we have left is to find the height.
h=25120/(400π)
h≈20mm
Now that we know the height, we can find the height of a single chip. The problem states about 50 chips can fit in a case. To find the height of a single chip, you would divide 20 by 50.
20mm/50 chips=0.4mm/chip.
When the corner is cut to a dimension of x, then the flap folded up, its height will be x. The appropriate choice is the last one, ...
(25 -2x)(20 -2x)x
Answer:
JK = 14 , IJ = 7
Step-by-step explanation:
Since K bisects JL , then
JK = KL = 14 , that is
JK = 14
------------------------------------
IJ = IL - JL = 35 - (2 × 14) = 35 - 28 = 7 , that is
IJ = 7