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sergeinik [125]
3 years ago
15

Please help! Urgent

Mathematics
1 answer:
mote1985 [20]3 years ago
5 0

Answer:

You Probably took the test and got a good grade!

Step-by-step explanation:

I need help myself so tell me what the answer is lol

Stay Positive!

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What is the arc measure of AC in degrees?
Mariulka [41]

Answer:

111

Step-by-step explanation:

simce p is the midppoint we kniw that AB is 180 so if you subtract 180 from 69 you get 111

8 0
3 years ago
drawbridge at the entrance to an ancient castle is raised and lowered by a pair of chains. The figure represents the drawbridge
jasenka [17]

Answer:

4.0 meters, ∠C = 39°, ∠A = 51°

Step-by-step explanation:

Firstly, our diagram shows us that the given triangle is actually a right triangle. So we can use the <em>Pythagorean Theorem</em> to solve for the height of the chain:

a^{2} +b^{2} =c^{2}

(3.3)^{2} +b^{2} =(5.2)^{2}

b^{2} =(5.2)^{2}-(3.3)^{2}

b =\sqrt{(5.2)^{2}-(3.3)^{2}}

b=4.0187...

b=4.0 m

Now, we can use the <em>Law of Cosines</em> to figure out one of the acute angles:

c^{2}  =a^{2} +b^{2} -2ab(cos(C))

(3.3)^{2}  =(4.0)^{2} +(5.2)^{2} -2(4.0)(5.2)(cos(C))

cos(C)=\frac{(3.3)^{2}-(4.0)^{2} -(5.2)^{2}}{-2(4.0)(5.2)}

C=cos^{-1}( \frac{(3.3)^{2}-(4.0)^{2} -(5.2)^{2}}{-2(4.0)(5.2)})

C=39.3915...

∠C = 39°

And since we know that all angles in a triangle add up to 180°:

∠A + ∠B + ∠C = 180

∠A + 90 + 39 = 180

∠A = 180 - 90 - 39

∠A = 51°

However, you should always review any answers on the Internet and make sure they are correct! Check my work to see if I made any mistakes!

7 0
3 years ago
Given that two tangent lines are constructed from the shared point A outside a circle to the points of tangency B and C, what is
Talja [164]
The answer would be C! Like the person stated above ''tangents to the same circle from the same point measure the same''.
3 0
3 years ago
Read 2 more answers
What is the area of this figure?
oksano4ka [1.4K]

Answer: i eat fooood bro

Step-by-step explanation:

7 0
3 years ago
Use ΔABC below to answer the question that follows:
Elza [17]

Answer:


Step-by-step explanation:

To prove Δ ABC similar to ΔDBE  we can consider

Segments AC and DE are parallel.

⇒ DE intersects AB and BC in same ratio.

AB is a transversal line passing AC and DE.

⇒∠BAC=∠BDE [corresponding angles]

Angle B is congruent to itself due to the reflexive property.

All of them are telling a relation of parts of ΔABC to ΔDBE.

The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".

4 0
3 years ago
Read 2 more answers
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