We assume the composite figure is a cone of radius 10 inches and slant height 15 inches set atop a hemisphere of radius 10 inches.
The formula for the volume of a cone makes use of the height of the apex above the base, so we need to use the Pythagorean theorem to find that. h = √((15 in)² - (10 in)²) = √115 in
The volume of the conical part of the figure is then V = (1/3)Bh = (1/3)(π×(10 in)²×(√115 in) = (100π√115)/3 in³ ≈ 1122.994 in³
The volume of the hemispherical part of the figure is given by V = (2/3)π×r³ = (2/3)π×(10 in)³ = 2000π/3 in³ ≈ 2094.395 in³
Then the total volume of the figure is V = (volume of conical part) + (volume of hemispherical part) V = (100π√115)/3 in³ + 2000π/3 in³ V = (100π/3)(20 + √115) in³ V ≈ 3217.39 in³
F ( x ) = ( 3 x + 6 ) ( 3 x - 6 ) / ( 3 x + 6 ) = 3 x - 6 and for domain : 3 x + 6 ≠ 0 3 x ≠ - 6 x ≠ - 2 anwser graph of 3 x - 6, with discontinuity at - 2
