Answer:
$150
Step-by-step explanation:
Let n = the number of students and
Let x = the contribution per student.
We have two conditions:
(1) 12 900 = nx
(2) 12 900 = (n+14)(x - 21)
Set (1) = (2) nx = (n+14)(x - 21)
Remove parentheses: nx = nx - 21n + 14 x - 294
Subtract nx from each side 0 = -21n + 14x - 294
Divide each side by -7 (3) 0 = 3n - 2x + 42
Divide each side of (1) by x (4) n = 12 900/x
Substitute (4) into (3) 0 = (3 × 12 900)/x - 2x + 42
0 = 38 700/x - 2x + 42
Multiply each side by x 0 = 38 700 - 2x² + 42x
Multiply each side by -1 0 = 2x² - 42x - 38 700
Solve the quadratic equation
x = [-b±√(b² - 4ac)]/(2a)
x = {42 ± √[(42² - 4×2(-38700)]}/(2 × 2)
= [42 ± √(1764 +309 600]/4
= [42 ± √(311 364)]/4
= (42 ± 558)/4
= 600/4
= 150
Each student contributes $150.
Answer:
5 = a whole big mac right so if you get a triple big mac divide the big mac to the other one
Step-by-step explanation:
Answer:
Your answer of
is correct
Step-by-step explanation:
We begin with the expression: ![-\frac{4}{y} +(-\frac{7}{8y} )](https://tex.z-dn.net/?f=-%5Cfrac%7B4%7D%7By%7D%20%2B%28-%5Cfrac%7B7%7D%7B8y%7D%20%29)
First, we need to find a common denominator, which in this case would be 8y.
To make the first term have a denominator of 8y, we must multiply it by ![\frac{8}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B8%7D)
![-\frac{4}{y}(\frac{8}{8}) +(-\frac{7}{8y} )\\\\-\frac{32}{8y} +(-\frac{7}{8y} )](https://tex.z-dn.net/?f=-%5Cfrac%7B4%7D%7By%7D%28%5Cfrac%7B8%7D%7B8%7D%29%20%20%2B%28-%5Cfrac%7B7%7D%7B8y%7D%20%29%5C%5C%5C%5C-%5Cfrac%7B32%7D%7B8y%7D%20%2B%28-%5Cfrac%7B7%7D%7B8y%7D%20%29)
Now we can add them to get our final answer.
![-\frac{39}{8y}](https://tex.z-dn.net/?f=-%5Cfrac%7B39%7D%7B8y%7D)
y = ln(x) - 5
For y = f(x),
y = f(x) + a
translates the function vertically by a units.
Answer:
The original number was: x = 0
Step-by-step explanation:
Let 'x' be the number
Given that:
Dan first divides it by 5
x/5
Then adds 3
x/5 + 3
To get an answer of 3
x/5 + 3 = 3
now solving the expression
![\frac{x}{5}+3=3](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B5%7D%2B3%3D3)
Subtract 3 from both sides
![\frac{x}{5}+3-3=3-3](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B5%7D%2B3-3%3D3-3)
Simplify
![\frac{x}{5}=0](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B5%7D%3D0)
Multiply both sides by 5
![\frac{5x}{5}=0\cdot \:5](https://tex.z-dn.net/?f=%5Cfrac%7B5x%7D%7B5%7D%3D0%5Ccdot%20%5C%3A5)
Simplify
![x=0](https://tex.z-dn.net/?f=x%3D0)
Therefore, the original number was: x = 0