Answer:
the last three
Step-by-step explanation:
cuz im big brains like that
The length and width are 1 and 13 ft.
w(w-12)=13
w^2-12w-13=0
w^2+w-13w-13
w(w+1) -13(w+1)
(w-13)(w+1)
w=13
w-12
13-12
1
Answer:
Let the speed of the train be x km/h.
Case 1:
Distance = 288 km
Speed = x km/h
Time = Distance/Speed
= 288/x h
Case 2:
Distance = 288 km
Speed = (x+4) km/h
Time = 288/x + 4 h
Since 288/x > 288/x + 4
288/x - 288/x+4 = 1
288[1/x - 1/x+4 ] = 1
[ x + 4 - x / x(x + 4) ] = 1/288
[4 / x^2 + 4x ] = 1/288
x^2 + 4x = 1152
x^2 + 4x - 1152 = 0
x^2 + 36x - 32x - 1152 = 0
x(x + 36) - 32(x + 36) = 0
(x + 36)(x - 32) = 0
x + 36 = 0 , x - 32 = 0
x = -36 , x = 32
x = -36 , rejected since speed cannot be negative.
Therefore , speed of the train = 32 km/h
Answer:
Step-by-step explanation:
i am not do sure but i think its in the ones place...
-sorry if im wrong
Answer:
6
Step-by-step explanation:
Given I varies inversely with R then the equation relating them is
I = 
← k is the constant of variation
To find k use the condition R = 12 when I = 3
k = IR = 3 × 12 = 36
I = 
← equation of variation
When I = 6, then
6 = , hence
R = 
= 6
