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3 years ago

Here is a probability scale

Mathematics

1 answer:

xxMikexx [17]3 years ago

5 0

Answer:

a) e

b) c

c) a

Step-by-step explanation: Look at the number line. 0 shows that it has no probability while C is at 1/2 showing that it could be half-half. Then you can see one under E which means it is bound to happen.

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So i'm really confused how do you get 3 5/12 in this question? Manson bought 8 1/4 feet of wire. He cut off a piece of wire 3 5/

GaryK [48]

Answer:

r = π C , C = 12 − x , t h e n r = π ( 12 − x ) = 12 π − π x

Step-by-step explanation:

So cutting the wire of 12 m in length into two pieces, x and 12-x. The x side will be made into the square so that the square has sides x/4 and an area of (x/4)^2. This means the length of the wire 12-x will be the circumference of the circle. So if: r = π C , C = 12 − x , t h e n r = π ( 12 − x ) = 12 π − π x i hope this is correct

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3 years ago

Complete the equation so that it has solutions of –5 and 7.<br> +<br> = 0

nekit [7.7K]

Answer:

the answer is - 2

Step-by-step explanation:

7-5=2-2=0

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3 years ago

By 8:00 a.M,, the snack bar had made 3,256 in sales. By noon the snack bar total sales were 8,821 About how much money did snack

marissa [1.9K]

5,565, if you subtract the 2 numbers

6 0

3 years ago

The graph below shows a proportional relationship between y and x. What is the constant of proportionality, y/x?

steposvetlana [31]

Answer:

1,40

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

a 4.50 g coin of copper absorbed 54 calories of heat. what was the final temperature of the copper if the initial temperature wa

I am Lyosha [343]

The final temperature of copper is 155.43°C.

Step-by-step explanation:

The formula to apply is Q=m*Δt*c where ;

Q=heat energy, m=mass, c=specific heat capacity and Δt= change in temperature

Given that Q=54 calories , m=4.50 g and c=0.092 cal/g°C

In this question find Δt then ,the final temperature.

Δt=Q/m*c

Δt=54/4.50*0.092 =130.43°C

To find final temperature, apply the formula;

Δt=Final temperature - Initial temperature

130.43°C=Final temperature-25°C

130.43°C+25°C=Final temperature

155.43°C

Learn More

Specific Heat Capacity : brainly.com/question/12431744

Keyword : specific heat capacity

#LearnwithBrainly

3 0

3 years ago