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Alika [10]
3 years ago
13

What is the solution set of the inequality x+2/2≥-7-x/2

Mathematics
2 answers:
PIT_PIT [208]3 years ago
5 0

Answer:

x\geq \frac{-16}{3}

Step-by-step explanation:

Kruka [31]3 years ago
3 0

Answer:

x\geq - \frac{16}{3}

Step-by-step explanation:

x +2/2 ≥ -7 - x/2

= x ≥ -16/3 (sign doesn't change since you didn't divide by a negative number).

<em><u>Ace Carlos</u></em>

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10.13+k≤26.83

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k≤16.70 or 16.7

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A basketball player has made​ 70% of his foul shots during the season. If he shoots 3 foul shots in​ tonight's game, what is the
yulyashka [42]

Answer:

There is a 34.3% probability that he makes all of the​ shots.

Step-by-step explanation:

For each foul shot that he takes during the game, there are only two possible outcomes. Either he makes it, or he misses. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 3, p = 0.7

What is the probability that he makes all of the​ shots?

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.7)^{3}.(0.3)^{0} = 0.343

There is a 34.3% probability that he makes all of the​ shots.

7 0
3 years ago
The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=
inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0  

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 :  P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125

Hence P(Y=1|X=3)=0.125

8 0
3 years ago
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