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3 years ago

Which of these shapes have the same area?? help ;-;

Mathematics

2 answers:

elixir [45]3 years ago

6 0

The answer would be A and B

kap26 [50]3 years ago

5 0

Answer:

A and B because if you count they both have 16 and C has 25

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Water fills a tank at a rate of 150 litres during the first hour, 350 litres during the second, 550 litres during the third and

Alborosie

Putting this as an arithmetic sequence gives:

$u_n = 150+200(n-1)$

The sum of the series = 16 x 7 x 7 = 784 m^3 = 784 000 L

The sum of an arithmetic series can be written as:

$S_n=n/2 [2a+(n-1)d] = 784 000
\\n/2[2(150)+(n-1)200] = 784 000
\\n[300+200(n-1)=1 568 000
\\300n+200n^2-200n = 1 568 000
\\200n^2+100n- 1 568 000 = 0
\\2n^2 +n- 15680 = 0

\\n= 88.2...,-88.7$

n has to be positive, so we get

n = 88.2 hours (3 s.f.)

3 0

3 years ago

Read 2 more answers

Find the volume of the cylinder

posledela

Answer:

I nk a ......................

8 0

2 years ago

Six times the lesser of the two consecutive even integers is 4 times the greater even integer. What are the integers?

Paladinen [302]

Answer:

Integers are 4 and 6

Step-by-step explanation:

Let the two consecutive even integers be $x,x+2$ such that $x$

Six times the lesser of the two consecutive even integers is 4 times the greater even integer.

So,

$6x=4(x+2)\\6x=4x+8\\6x-4x=8\\2x=8\\x=4$

Other integer $=x+2=4+2=6$

5 0

3 years ago

QUESTION 11.1

lawyer [7]

The group paid $ 5250 at first city and $ 6250 at second city

Solution:

Let x = the charge in 1st city before taxes

Let y = the charge in 2nd city before taxes

The hotel charge before tax in the second city was $1000 higher than in the first

Then the charge at the second hotel before tax will be x + 1000

y = x + 1000 ----- eqn 1

The tax in the first city was 8.5% and the tax in the second city was 5.5%

The total hotel tax paid for the two cities was $790

Therefore, a equation is framed as:

8.5 % of x + 5.5 % of y = 790

$\frac{8.5}{100} \times x + \frac{5.5}{100} \times y = 790$

0.085x + 0.055y = 790 ------- eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 1 in eqn 2

0.085x + 0.055(x + 1000) = 790

0.085x + 0.055x + 55 = 790

0.14x = 790 - 55

0.14x = 735

Substitute x = 5250 in eqn 1

y = 5250 + 1000

Thus the group paid $ 5250 at first city and $ 6250 at second city

8 0

3 years ago

please help me figure out how to determine the range of the following graph (the line y=5 is a horizontal asymptote)

prisoha [69]

we are given the graph of the function and we are interested in finding the range of the function. Recall that the range of a graph is simply the set of values on the y axis, for which there is a point on the graph that has that y coordinate.

One easy way to spot this set, is by taking any point on the graph and then drawing a horizontal line. Wherever the line crosses the y axis, that point is included in the range.

From the graph, we can see that no part of the graph has values with y coordinate less than 5. That is, any number less than 5 in the y coordinate would indicate that there is no point on the graph at that "height". So every number less than 5 is excluded from the range.

We are also told that line y=5 is a horizontal asymptote. This means that despite the graph is really close to the line y=5 (and it keeps getting closer and closer as x increases), it never touches the line. This means that the point 5 is excluded from the range.

Finally, we can see that above the horizontal line y=5, if we draw a horizontal line on the graph, it will touch the y axis. This means that every number greater than 5 is part of the range. Then, the set of numbers that represent the range is

$(5,\text{infinity)}$

4 0

11 months ago