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enyata [817]
3 years ago
11

A man (M) is standing on the bank of a river that is 0.9 miles wide. He wants to reach a house (B) on the opposite shore that is

0.9 miles downstream. The man can row the boat 3 mph and can walk 4.5mph. Find the distance between the house and the point (P) where he should dock his boat in order to minimize the total time he would need to reach the house. Enter the exact answer or round to the nearest hundredth.
Mathematics
1 answer:
atroni [7]3 years ago
3 0

Answer:

The distance between the hose and the point (P) is 0.9 miles

Step-by-step explanation:

Here we have

Speed of rowing the boat = 3 mph

Speed of waling = 4.5 mph

Since the speed of walking is more than that of to row the  boat, the location of where he should dock his boat in order to minimize the total time he would need to reach the house is the shortest distance across the river to the house

Therefore the location of the point (P) should be directly opposite the house across the water and the distance id 0.9 miles.

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Answer:

a. 24 ÷ 3  = 8                       ⇒              i. 8 × 3 ÷ (6 − 3)  = 8

b. 53 × 7 = 371                     ⇒             h. (8 × 7 − 3) × 7 = 371

g. 8 × (5 × 12 − 10) = 400    ⇒             f. 8 × 50 = 400

Step-by-step explanation:

Given:

We have to match the equivalent expressions:

a. 24 ÷ 3                 f. 8 × 50

b. 53 × 7                 g. 8 × (5 × 12 − 10)

c. 56 − 21               h. (8 × 7 − 3) × 7

d. 4 − 3                   i. 8 × 3 ÷ (6 − 3)

                e. 40 × 2          

             

Solution:

a. 24 ÷ 3 = 8                

b. 53 × 7 = 371            

c. 56 − 21 = 35            

d. 4 − 3 = 1  

e. 40 × 2 =80                            

f. 8 × 50 = 400                      

g. 8 × (5 × 12 − 10)  <em>Using PEMDAS rule.</em>

⇒ 8\times (60-10)

⇒ 8\times 50

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⇒ (56-3)\times 7

⇒ (53)\times 7

⇒ 371

i. 8 × 3 ÷ (6 − 3) = 8

⇒ \frac{8\times 3}{3}

⇒ \frac{24}{3}

⇒ 8

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g. 8 × (5 × 12 − 10) = 400    ⇒             f. 8 × 50 = 400

c,d and e didn't have any match    

a is equivalent to i,b equivalent to h and g is equivalent to f.

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