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Nataly_w [17]
3 years ago
6

Given that AD and BC bisect each other at E, prove that ⦟B ≅⦟D.

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

answer is 0.15 tell me if ot is right

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A diver jumps up and over from a cliff in order to avoid rocks and land in the deeper water. The path of the dive can be modeled
lions [1.4K]

Answer:

48.06  to the nearest hundredth.

Step-by-step explanation:

f(x) = -16x^2 + 2x + 48

To find the maximum height we convert to vertex form:

= -16(x^2 + 1/8x) + 48

= -16[x + 1/16)^2 - 1/256] + 48

= -16(x + 1.16)^2  + 16/256 + 48

= 48.0625.

4 0
3 years ago
chegg evaluate the following integral using trigonometric substitution. dx/square root(x^2-81), x > 9
vesna_86 [32]

Integration will be ln | ( x /9 ) + ( \sqrt{(x/9)^{2} - 1 } ) | + c  .

Given  ∫ 1 dx / ( x^{2} - 81 )

Put ,

x = 9 secθ

dx = 9 secθ tanθ dθ

and

\sqrt{x^{2}  - 9^{2} } = 9 tanθ

Substituting values in  ∫ 1 dx / ( x^{2} - 81 ) ,

∫ (9 secθ tanθ ) dθ / ( 9 tanθ )

∫ secθ dθ = ln | secθ + tanθ | + c

                = ln | ( x /9 ) + ( \sqrt{x^{2}  - 9^{2} } / 9 ) | + c

              = ln | ( x /9 ) + ( \sqrt{(x/9)^{2} - 1 } ) | + c

Hence , the integration will be ln | ( x /9 ) + ( \sqrt{(x/9)^{2} - 1 } ) | + c .

To learn more on integration follow link :

brainly.com/question/20156869

#SPJ4

6 0
2 years ago
Which table represents a linear function? HELP FAST PLEASE
borishaifa [10]

Answer:

the bottom left

Step-by-step explanation:

A linear function will have a constant slope so the bottom left graph is the only one with a constant slope. The y-values are all increasing by 2.

7 0
2 years ago
ou have a bag of chocolate candy. Ten of them are red, 7 are brown, 12 are green, and 9 are blue. What is the probability that y
ladessa [460]
D)))))) 9 hhhhhhhhhhhhhhhhhhhhhhhhhhhh
7 0
3 years ago
Read 2 more answers
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
3 years ago
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