1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lana66690 [7]
2 years ago
14

The total simple interest on $1600 invested for five years is $224. What is the percentage rate per annum?

Mathematics
2 answers:
oksano4ka [1.4K]2 years ago
7 0

Step-by-step explanation:

did u got the answer??.....

mash [69]2 years ago
6 0

Answer:

The percentage rate per annum is 2.8%

Step-by-step explanation:

We need to multiply the principal by the time, then divide the interest by the product of P×T, so:

1,600 × 5 = 8,000

224 ÷ 8,000 = 0.028

Then we convert our final product to a percentage.

0.028 to a percent is 2.8%

You might be interested in
Seven subtracted from the product of 5 and a number is at least 24
Dovator [93]

Answer:

5a-7=24

5a=24+7

a=31/5

Step-by-step explanation:

8 0
3 years ago
there are 49 dogs signed up for the dog show. there are 36 more small dogs than large dogs. how many small dogs are signed up fo
pogonyaev
Okay, so total dogs are 49.
So we know if x=large dogs and y=small dogs, then x+y=49.
Next we are told that there are 36 MORE small dogs than large dogs. We can take that more meaning addition, and x being our value for large dogs. So y=x+36.
After that we now know what value we can plug in for y. So x+x+36=49.
We can then simplify it to 2x+36=49.
Subtracting the 36 from both sides, leaves you with 2x=13.
Followed by dividing both sides by 2, gives you x=6.5. Or 6.5 large dogs.
Now we can plug this into our formula for the small dogs (y=x+36) to give us y=6.5+36, which simplifies to y=42.5. Or 42.5 small dogs. Which is our answer.
We can double check it by adding the small and large dogs together, 6.5+42.5, which gives us 49, our total entries.
4 0
4 years ago
Read 2 more answers
Help if your gonna answer plz explain it
Katyanochek1 [597]

So you wanna find the area of each surface:

For the large square surface in the top you do 12*15=180 and there are two large squares faces so you multiply 180 by 2 which equals 360 then you find the small rectangle faces: 5*15=75 and multiply by 2 Bc there are 2 faces like that so it would be 75*2=150 then for the last faces you do 12*5= 60 *2= 120 at the end I add all of the faces up, 360+150+120=630

6 0
4 years ago
Which of the following values is not a perfect square?<br> a.81<br> b.125<br> c.49<br> d.100
SashulF [63]

Answer: b. 125

Step-by-step explanation:

Find the square roots of each, and if the square root is a decimal, it is not a perfect square.

Square root of 81: 9

Square root of 49: 7

Square root of 100: 10

That leaves 125.

4 0
2 years ago
Read 2 more answers
Can someone pls help with this
Anon25 [30]

Answer:

sorry i cant figure this out

7 0
3 years ago
Other questions:
  • What are zeros of f(x)=x^2-3x-18. and please explain so I can see if I can understand.
    11·1 answer
  • Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
    6·1 answer
  • You have two credit cards. One has a balance of $3,745.00 at a 6.25% APR and the other has a balance of $1,045.00 and is depende
    5·2 answers
  • What is the simplified form of ether following expression ?
    11·2 answers
  • Which decimal is greater 0.7 or 0.07?
    15·2 answers
  • Help me please i’ll give extra points
    6·2 answers
  • Jensen recorded the daily average temperature (in degrees Fahrenheit) at his home over two weeks' time. ​His results are shown b
    7·1 answer
  • The spherical bottle has a conical shaped lid with a diameter of 5cm and a height of 4.5cm. Given this information, calculate th
    8·1 answer
  • What id the height of the triangle?​
    15·2 answers
  • Please answer the question in the picture
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!