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nasty-shy [4]
3 years ago
7

Simplify this equation Thanks a lot!!!

Mathematics
1 answer:
den301095 [7]3 years ago
4 0

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

\bf\implies a^m \times b^m = (ab)^m

Using this property , we have ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

This can be written as ,

\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}

Simplifying using ( a+b)(a-b) = a² - b² ,

\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}

Subtracting the numbers inside the brackets ,

\rm\implies (-1)^{2n - 1 }

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the <u>power is odd</u> .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

\rm\implies\boxed{\quad \red{ -1 }\quad }

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>.</u>

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Answer:

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4 0
1 year ago
Find the radical equivalent of 27^2/3 and compute it.<br> please help i'm taking a test.
AveGali [126]
Note that (a^b)^c=a^(bc) so in this case we have:

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I am assuming that you meant 27^(2/3)
6 0
3 years ago
Read 2 more answers
Please help!!! I need this done today!!
Kryger [21]

Answer:

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now, if time = 1.6 hrs.

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= 25 x 1.6 = 40.0 mi

---------------------------------------------------------------------------------------------

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8 0
3 years ago
Select the correct answer.
mariarad [96]

The answer to this Question is A

What is Absolute Value Function or so called Modulus Function or Mod function?

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Solution:

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4 0
1 year ago
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Answer:

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5 0
3 years ago
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