Answer:
period
Step-by-step explanation:
The attached graph shows a period of the function. Its amplitude is 1/4 (vertical distance from centerline to peak). Its period is 4π (horizontal distance from peak to peak). Its frequency is the reciprocal of the period, so would be 1/(4π).
The value 4π is the period of the function.
b
(-12+-2)/2 ,(6+-5)/2
(z+6)(z+6): z ^ 2 + 12z + 36
(x+5)(x+5): x ^ 2 + 10x + 25