The mean weight of five complete computer stations is 167.2 pounds.
The weights of four of the computer stations are 158.4 pounds, 162.8 pounds, 165 pounds, and 178.2 pounds.
We have to determine the weight of fifth computer station.
Let the weight of fifth computer station be 'x' pounds.
Mean is calculated by sum of all the observations divided by the total number of observations.
So, 



x= 171.6 pounds
The weight of fifth computer station is 171.6 pounds.
Answer:
4x^2 - 16x - 48 = 0.
Step-by-step explanation:
In a factor form it is:
4(x + 2)(x - 6) = 0
Convert to standard form:
4(x^2 - 4x - 12) = 0
4x^2 - 16x - 48 = 0.
The correct answer is C.
-5 is not greater than -3. Negatives are tricky; remember that the closer a negative is to zero, the greater that quantity actually is.
Answer:
The variable x will follow a geometric distribution, with mean = 3 and standard deviation = 3.46.
The values for P(x) are:

Step-by-step explanation:
This kind of random variables can be descripted by the geometrical distribution.
This distribution shows the probability of having an amount of "failures" before the first "success" (or the other way).
Let x be the number of trustworthy FBI agents tested until someone fails the test. The probability of failing a test is p=0.25
Then, the probability of x is:

The values for the first x are:

This probability will be descending as the the variable x increases.
The mean is:

The standard deviation is:

Answer:
2n^2 + n + 4.
Step-by-step explanation:
7, 14, 25, 40, 59
The differences are 7, 11, 15, 19 which is arithmetic sequence so the given sequence is quadratic.
Compile a table:
n 1 2 3 4 5
term 7 14 25 40 59
Diff: 7 11 15 19
Diff: 4 4 4 - this indicates that first part is 2n^2.
2n^2 2 8 18 32 50
term-2n^2 5 6 7 8 9
- the nth term for the last sequence is 5+ (n - 1)d =
= 5 + (n - 1)* 1
= n + 4.
So nth term for the original sequence is 2n^2 + n + 4.