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lbvjy [14]
2 years ago
10

Which expression can be used to determine the skip of the linear function represented in the table

Mathematics
2 answers:
masha68 [24]2 years ago
8 0
The correct answer is c
gavmur [86]2 years ago
3 0

Answer:

i think it is c!

Step-by-step explanation:

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What is the recursive rule for the sequence -22.7, -18.4, -14.1, -9.8, -5.5
nikklg [1K]
The answer would be d.) An=An+1-4.3
6 0
3 years ago
Read 2 more answers
Find the length of line segment UV.
pshichka [43]

Answer:

The length of the line segment UV is 76 units

Step-by-step explanation:

In a triangle, the line segment joining the mid-points of two sides is parallel to the third side and equal to half its length

In Δ ONT

∵ U is the mid-point of ON

∵ V is the mid-point of TN

→ That means UV is joining the mid-points of two sides

∴ UV // OT

∴ UV = \frac{1}{2} OT

∵ UV = 7x - 8

∵ OT = 12x + 8

∴ 7x - 8 = \frac{1}{2} (12x + 8)

→ Multiply the bracket by \frac{1}{2}

∵ \frac{1}{2} (12x + 8) =  \frac{1}{2} (12x) +  \frac{1}{2} (8) = 6x + 4

∴ 7x - 8 = 6x + 4

→ Add 8 to both sides

∴ 7x - 8 + 8 = 6x + 4 + 8

∴ 7x = 6x + 12

→ Subtract 6x from both sides

∴ 7x - 6x = 6x - 6x + 12

∴ x = 12

→ Substitute the value of x in the expression of UV to find it

∵ UV = 7(12) - 8 = 84 - 8

∴ UV = 76

∴ The length of the line segment UV is 76 units

8 0
2 years ago
-2 1/2 * (1 2/3) = what?
TiliK225 [7]

Answer:

4.16

Step-by-step explanation:

Mixed Number = 4 1/6

Decimal = 4.16

Fraction = 4.1666666

Percentage = 416%

7 0
2 years ago
Read 2 more answers
What is<br><img src="https://tex.z-dn.net/?f=1895%20%5Ctimes%20906" id="TexFormula1" title="1895 \times 906" alt="1895 \times 90
netineya [11]

Answer:

1895 x 906=

1,716,870

4 0
3 years ago
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

4 0
3 years ago
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