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3 years ago

What is the surface area of a sphere with a radius of 5 in

Mathematics

1 answer:

Naddik [55]3 years ago

7 0

Answer:

314.16 inches

Step-by-step explanation:

The surface area of a sphere is:

$A_{sphere}=4\pi r^2$

if the radius is 5 inches then:

$A_{sphere}=4 \pi (5)^2 = 4\pi (25)=100 \pi \approx 314.16 in.$

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ATB is a tangent to the circle centre O. Find the values of x y and z in each case.

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3 years ago

PLEASE HELP 25 POINTS!!

eduard

Answer:

(27 y^(-8))/(4 x^6)

Step-by-step explanation:

Simplify the following:

(4 (3 x^2 y^4)^3)/(2 x^3 y^5)^4

Multiply each exponent in 2 x^3 y^5 by 4:

(4 (3 x^2 y^4)^3)/(2^4 x^(4×3) y^(4×5))

4×5 = 20:

(4 (3 x^2 y^4)^3)/(2^4 x^(4×3) y^20)

4×3 = 12:

(4 (3 x^2 y^4)^3)/(2^4 x^12 y^20)

2^4 = (2^2)^2:

(4 (3 x^2 y^4)^3)/((2^2)^2 x^12 y^20)

2^2 = 4:

(4 (3 x^2 y^4)^3)/(4^2 x^12 y^20)

4^2 = 16:

(4 (3 x^2 y^4)^3)/(16 x^12 y^20)

Multiply each exponent in 3 x^2 y^4 by 3:

(4×3^3 x^(3×2) y^(3×4))/(16 x^12 y^20)

3×4 = 12:

(4×3^3 x^(3×2) y^12)/(16 x^12 y^20)

3×2 = 6:

(4×3^3 x^6 y^12)/(16 x^12 y^20)

3^3 = 3×3^2:

(4×3×3^2 x^6 y^12)/(16 x^12 y^20)

3^2 = 9:

(4×3×9 x^6 y^12)/(16 x^12 y^20)

3×9 = 27:

(4×27 x^6 y^12)/(16 x^12 y^20)

4/16 = 4/(4×4) = 1/4:

(27 x^6 y^12)/(4 x^12 y^20)

Combine powers. (27 x^6 y^12)/(4 x^12 y^20) = (27 x^(6 - 12) y^(12 - 20))/4:

(27 x^(6 - 12) y^(12 - 20))/4

6 - 12 = -6:

(27 x^(-6) y^(12 - 20))/4

12 - 20 = -8:

Answer: (27 y^(-8))/(4 x^6)

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3 years ago

I need help RATS :) EHEHEHEHEHEHEEHEHEHEHEHEHEHEHEHEHEEHEHHEHEEHEHEH

galina1969 [7]

Answer:

Ok, so the answer is 3.5

Step-by-step explanation:

From what I could see it says walked for 14 around her block 4 times so your answer is 3.5 because if (Let's call her Patricia) Patricia walked around her block 4 times in 14 minutes, we have to find the unit rate, therefore we have to divide 14 by 4 as shown below

$14/4=3.5$

Thus your only viable solution is 3.5

Hope this Helps! Also, I would appreciate it if I could be rewarded with Brainliest, I work hard on these answers and I would enjoy it, you see my goal is to reach Genius status, as to provide many more helpful answers and help many more people. Even so, I hope that I have come of assistance to you!

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