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fredd [130]
3 years ago
5

Jimarcus plans to build a fence that is 5 1/3 yards long at the back of his garden. How many 2/3 - yard sections of fence will h

e need?
Mathematics
1 answer:
muminat3 years ago
3 0
He will need eight 2/3 yard sections of fence
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The length of a certain lot if 20 feet less than four times its width. the area of 4200 sq. ft. what are the dimensions of the l
tia_tia [17]
The area of a surface is the number of square units present in the surface. For a rectangle, it is calculated from the product of the length and the width. To determine the length and width of the lot given above, we first assume that it is in a rectangular shape which is defined by its length and its width. We are given the following:

Area = 4200 square feet
Length = 4x - 20 feet
Width = x feet

From the definition of the area of a rectangle,

Area = length x width
4200 = (4x -20) (x)
4200 = 4x^2 - 20x
4x^2 - 20x - 4200 = 0
4(x^2 - 5x - 1050) = 0
x^2 - 5x -1050 = 0

Factoring the equation would lead to:
(x - 35) (x +30) = 0
x -35 = 0 ; x = 35
x + 30 = 0 ; x = -30

The width should not be a negative value so the width would be equal to 35 feet. So, the length would be 

Length = 4(35) - 20 = 120 feet

3 0
3 years ago
PLEASE HURRY<br> solve for x. <br> 3(x + 5) - 2(x + 2) =20 <br><br> 1.) 1<br> 2.) 9<br> 3.) 13
muminat

Answer:

The answer is X=9

Step-by-step explanation:

Remove the parentheses

Collect the like terms, subtract

Move the constant to the right

Subtract the leftover numbers

X=9

4 0
3 years ago
Solve for x in the diagram below.<br> (2 +40)<br> 60°
Yakvenalex [24]

Answer:

20°

Step-by-step explanation:

x+40=60 (vertically opposite angle)

or, x=60-40

or, x=20°

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15 times 5 = 75 so approx. $75
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6 12 18 24 30 36 42 48 
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