All categories

2 years ago

The sides of four triangles are given...

Mathematics

1 answer:

kari74 [83]2 years ago

3 0

Answer:

Triangle C is

Step-by-step explanation:

can i get brainliest answer pleaseeee

You might be interested in

Area of the figure: A)128 B)136 C)153 C)258

GarryVolchara [31]

Answer: 153

Step-by-step explanation:

area of rectangle= 16 x 3= 48

area of trapezium= 1/2(a+b)h

=1/2(16+5)x 10

=105

105+48= 153 in^2

3 0

3 years ago

Inez Walks 1.85 mi in 45 minutes , how many miles can she walk in 1 hour?

insens350 [35]

Answer:

She can walk 2.46 repeating miles in 1 hour

Step-by-step explanation:

We can write a proportion to solve this problem. Write the number of miles on top and the time in minutes on the bottom. We know 1 hour is 60 minutes.

1.85 miles x miles

------------------- = ----------------------

45 miles 60 minutes

Using cross products

1.85 * 60 = 45x

Divide each side by 45

1.85*60/45 = 45x/45

2.466666666 =x

She can walk 2.46 repeating miles in 1 hour

4 0

3 years ago

Simplify 22w/55 2/5 22/55 2w/11 2w/5

tangare [24]

Answer:

2w/5

Step-by-step explanation:

Divide whole numbers by 11,leave the variable.

4 0

3 years ago

Read 2 more answers

A circular well has a circumference of 7.85 yards. What us the diameter of the well

sergiy2304 [10]

15.7 that thy answer

6 0

3 years ago

Read 2 more answers

The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?

Paul [167]

Answer:

The standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is $M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (6,2) and (-2,5) respectively.

$M=(\frac{6-2}{2},\frac{2+5}{2})$

$M=(\frac{4}{2},\frac{7}{2})$

$M=(2,\frac{7}{2})$

Therefore the center (h,k) is $(2,\frac{7}{2})$

now to find the radius:

The diameter is the distance between the given points (6,2) and (-2,5)

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

$=\sqrt{(-2-6)^2+(5-2)^2}$

$=\sqrt{(-8)^2+(3)^2}$

$=\sqrt{64+9}$

$=\sqrt{73}$

Therefore the radius is $\sqrt{73}$

i.e., $r=\sqrt{73}$

Therefore the standard form of the circle is

$(x-h)^2+(y-k)^2=r^2$

Now substituting the center and radiuswe get

$(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2$

$(x-2)^2+(y-\frac{7}{2})^2=73$

Therefore the standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

5 0

3 years ago