Answer:
∠EFG = 48°
Step-by-step explanation:
As FH bisects ∠EFG , ∠EFH = ∠HFG .
We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°
Also, ∠HFG + ∠EFH = ∠EFG
=> 2(-5x + 89)° = (61 - x)°
=> -10x + 178 = 61 - x
=> 10x - x = 178 - 61
=> 9x = 117
=> x = 117 / 9 = 13
Putting the value of 'x' in ∠EFG gives :-
(61 - x)° = (61 - 13)° = 48°
Third length =
12-7 = 5
12+7 = 19
Third length can be only in this range
5Means the third length must be greater than 5 and less than 19.
Hope this helps!
Answer:
27 miles in the morning and 85 miles in the afternoon.
Explanation:
Let m be the number of miles they rode in the morning. They rode 4 more than 3 times this many in the afternoon; this gives us the expression
3m+4
to represent the miles ridden in the afternoon.
Together they rode 112 miles; this means we add the morning miles, m, to the afternoon miles, 3m+4, and get 112:
m+3m+4 = 112
Combine like terms:
4m+4 = 112
Subtract 4 from each side:
4m+4-4= 112-4
4m = 108
Divide both sides by 4:
4m/4 = 108/4
m = 27
They rode 27 miles in the morning.
That means in the afternoon, they rode
3m+4 = 3(27)+4 = 81+4 = 85 miles.
Answer: for the on your own the equation is y=2x for the outputs on the other thing just add the numbers up
Step-by-step explanation:
The answer to number 2 is g.15
