All categories

2 years ago

The sides of four triangles are given...

Mathematics

1 answer:

kari74 [83]2 years ago

3 0

Answer:

Triangle C is

Step-by-step explanation:

can i get brainliest answer pleaseeee

You might be interested in

Gehdidhdvrhsiwhscsujsbejd

zhannawk [14.2K]

Answer:

I agree completely

Step-by-step explanation:

3 0

2 years ago

Make Q the subject of the formula A = Q2 - 2a.

son4ous [18]

Answer:

$\huge\boxed{Q = \sqrt{A+2a}}$

Step-by-step explanation:

$A = Q^2 -2a$

Adding 2a to both sides

$Q^2 = A+2a$

Taking sqrt on both sides

$Q = \sqrt{A+2a}$

8 0

3 years ago

______ an argument which convinces other people that something is true

Alina [70]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.

lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

$PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ$

Likewise:

$\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ$

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

$m\angle PAC=m\angle PAB+m\angle BAC$

Likewise:

$m\angle QAB=m\angle QAC+m\angle BAC$

Since ∠QAC ≅ ∠PAB:

$m\angle PAC=m\angle QAC+m\angle BAC$

And by substitution:

$m\angle PAC=m\angle QAB$

Thus:

$\angle PAC\cong \angle QAB$

Then by SAS Congruence:

$\Delta PAC\cong \Delta BAQ$

And by CPCTC:

$PC\cong BQ$

5 0

2 years ago

Read 2 more answers

Solve The Problem -3+2x=7

BlackZzzverrR [31]

2x = 7 + 3
2x = 10
x = 10/2
x = 5
S: {5}

3 0

3 years ago

Read 2 more answers