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3241004551 [841]

3 years ago

14

What are the coordinates of the vertex of the table? Is it a minimum or a maximum?

2 answers:

Tatiana [17]3 years ago

8 0

You can reconstitute the equation of this quadratic function
of te form:y = ax² + bx + c, by giving x and y the various values in the table. For instance: for x = 0, y =1. Plug 0 & 1 in the equation:1 = a(0)² +b(0) + c → c = 1 . You continue with the other values and you will find :
a-b = -3 and
4a - 2b =- 4
Solving it will give y = x² +4x +1
This is a parabola opening upward (because a >0) with an axis of symmetry = -b/2a or x= -2 and a minimum y = (-2)² -2(4)+1 = -3; hence
MINIMUM (-2, -3).
N.B: Your various answers don't mention my result. However in your
C. Answer they are claiming Maximum (-2,-3) and it's wrong it should be MINIMUM.
Please refer to your teacher since I am sure of the result <span> </span>

REY [17]3 years ago

8 0

Answer:

The answer is the option B

$(-2,-3)$ is a minimum

Step-by-step explanation:

using a graphing tool

plot the ordered pairs of the table

Observing the points in the graph the less value of y is equal to $-3$

therefore

the point $(-2,-3)$ is a minimum

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Answer:

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Step-by-step explanation:

Because the equation for area is length times width, you would have to set the two equations to seventy and multiply them.

<em> (x+5) (x+2) = 70</em>

<em> </em><em>2x + 10 = 70</em>

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Lelechka [254]

Answer:

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What is the area of a rectangle that is 3.1 cm wide and 4.4 cm long? Enter the full-precision answer first to see the correspond

Brrunno [24]

Answer: Without rounding : 13.64 (square cm)

Rounded answer : 13.6(square cm)

Step-by-step explanation:

We know that the area of a rectangle is given by :-

$A=l\times w$ , where l is the length and w is the width of the rectangle.

Given : The dimensions of a rectangle are 3.1 cm wide and 4.4 cm long.

Then, the area of rectangle will be:-

$A=4.4\times 3.1=\dfrac{44}{10}\times\dfrac{31}{10}\\\\=\dfrac{1364}{100}=13.64\text{ cm}^2\approx13.6\ cm^2 \text{Rounded to the nearest tenth}$

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3 years ago

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