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2 years ago

Three triangles are shown.

Mathematics

1 answer:

Agata [3.3K]2 years ago

7 0

Answer:

I think that it may be the last one

Step-by-step explanation:

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Check all that apply

kogti [31]

Answer:

A & C

Step-by-step explanation:

The equation for a circle is (x – h)^2 + (y – k)^2 = r^2, with the center being at (h,k). On the x-axis would mean the x coordinate would equal 0, therefore A and C are your answers.

Hope I helped! :)

7 0

3 years ago

Read 2 more answers

Find the postive value of x when y = 25

tiny-mole [99]

2/5 , i dont have an explanation but maybe try that! I just did the math on paper

7 0

2 years ago

Read 2 more answers

Given the equation y = 2/3 x − 2, what is the value of x when y = 10?

SIZIF [17.4K]

Step-by-step explanation:

Y is equal to:

2/3x - 2 = 10

2/3x = 10 + 2

2/3x = 12

3/3x = (12 ÷ 2) × 3

x = 18

Not sure but its worth a try.

6 0

3 years ago

If the measure of angle 2 is 92 degrees and the measure of angle 4 is (one-half x) degrees, what is the value of x?

zavuch27 [327]

Answer: x = 184°

Step-by-step explanation: As we can see in the figure below, angles 2 and 4 are Vertical Angles, i.e., they are angles opposite each other when two lines cross. Vertical angles are always congruent.

Then,

m∠2 = m∠4

$92=x.(\frac{1}{2})$

$92=\frac{x}{2}$

Value of x is

$x=92(2)$

x = 184

The value of x is 184°.

4 0

3 years ago

A random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength

irinina [24]

Answer:

Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.

Step-by-step explanation:

We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.

Let $\bar X$ = sample mean comprehensive strength

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean comprehensive strength = 5500 psi

$\sigma$ = standard deviation = 100 psi

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P( $\bar X$ > 4985 psi)

P( $\bar X$ > 4985 psi) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{4985-5500}{\frac{100}{\sqrt{9} } }$ ) = P(Z > -15.45) = P(Z < 15.45)

= 0.99999

Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.

4 0

3 years ago