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sergeinik [125]
3 years ago
6

Three triangles are shown.

Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0

Answer:

I think that it may be the last one

Step-by-step explanation:

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Whats the length in meters of CD?​
Gnesinka [82]

Answer:

The length of DC in meters is  \frac{60}{13} ⇒ A

Step-by-step explanation:

In the circle O

∵ AB passing through O

∴ AB is a diameter

∵ D is on the circle

∴ ∠ADB is an inscribed angle subtended by arc AB

∵ Arc AB is half the circle

→ That means its measure is 180°

∴ m∠ADB = \frac{1}{2} × 180° = 90°

In ΔADB

∵ m∠ADB = 90°

∵ AD = 5 m

∵ BD = 12 m

→ By using Pythagorase Theorem

∵ (AB)² = (AD)² + (DB)²

∴ (AB)² = (5)² + (12)²

∴ (AB)² = 25 + 144 = 169

→ Take square root for both sides

∴ AB = 13 m

∵ ∠ADB is a right angle

∵ DC ⊥ AB

∴ DC × AB = AD × DB

→ Substitute the lengths of AB, AD, and DB

∵ DC × 13 = 5 × 12

∴ 13 DC = 60

→ Divide both sides by 13

∴ DC = \frac{60}{13} m

∴ The length of DC in meters is  \frac{60}{13}

6 0
2 years ago
Is 7/8 the right answer
kari74 [83]
Yes you would be correct!
6 0
3 years ago
Read 2 more answers
Plz help! Gonna need to turn it soon
Veseljchak [2.6K]

Answer:

C - 13*

Step-by-step explanation:

3 0
3 years ago
What is the volume of a right circular cone that has a height of 14.9 cm and a base with the circumference of 2.9 cm rounded to
xxMikexx [17]

Answer:

The answer to your question is  Volume = 3.30 cm³

Step-by-step explanation:

Data

Volume = ?

height = 14.9 cm

circumference = 2.9 cm

Process

1.- Calculate the radius

   circumference = 2πr

-Substitution

   2.9 = 2πr

-Solve for r

   r = 2.9/2π

   r = 1.45/π cm

2) Calculate the volume of the cone

   Volume = 1/3πr²h

-Substitution

   Volume = 1/3π(1.45/π)²(14.9)

-Simplify

   Volume = (1.04)(0.213)(14.9)

   Volume = 3.30 cm³

5 0
3 years ago
PLEASE HELP THID QUIZ DEPENDS ON MY GRADE<br> Match the function with the correct equation.
Leni [432]

Answer:

Exponential --> y=ab^x

Trigonometric --> y= sin x

Quadratic --> y= x^2

Rational -->y=1/x

7 0
2 years ago
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