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sergeinik [125]
3 years ago
6

Three triangles are shown.

Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0

Answer:

I think that it may be the last one

Step-by-step explanation:

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F(1)=3f(1)=3 and f(n)=2f(n-1)+3 <br><br> f(n)=2f(n−1)+3 <br><br> then find the value of f(3)
gayaneshka [121]

Answer:

f(3)=21

Step-by-step explanation:

f(1)=3

f(n)=2f(n-1)+3

n=2

f(2)=2f(2-1)+3

f(2)=2f(1)+3

f(2)=2*3+3

f(2)=6+3

f(2)=9

n=3

f(3)=2f(3-1)+3

f(3)=2f(2)+3

f(3)=2*9+3

f(3)=18+3

f(3)=21

7 0
3 years ago
Rolling a number less than 6 on a number cube labeled 1 through 6
marysya [2.9K]

Answer:

Any number from 1-5

Step-by-step explanation:

Less than 6!

6 0
3 years ago
Which option shows the following fractions written with a common<br>denominator?<br>8/9 and 3/8​
Mumz [18]

Answer:

72

Step-by-step explanation:

8/9 + 3/8

Multiply the denominators to get the common denominator

9x8 = 72.

4 0
3 years ago
Is (0, 2) a solution to the equation y=3x​
igor_vitrenko [27]

Answer:

no

Step-by-step explanation:

y = 3x

Substitute the point into the equation

2 = 3*0

2 =0

This is not true so the point is not a solution

6 0
3 years ago
Read 2 more answers
99 POINTS!!! JUST ANSWER THIS QUESTION, PLEASE!!!
-Dominant- [34]

Hi!

I would approach this question by first looking at where the parallelogram is located, by graphing the image. I did so and drew a rough image on Paint (See attached image)

To get the part where the diagonals intersect, I would find the midpoint of the line between points (1, 3) and (5,-9) (or the other pair). The reason is a parallelogram's diagonals always bisect each other, meaning the point they intersect is always the middle of the two diagonals.

Therefore, you can find the midpoint of a diagonal, between (1, 3) and (5, -9). The midpoint theorem is (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}.

Take the points (1, 3) and (5, -9), and fill them in.

(\frac{1 + 5}{2} , \frac{3 - 9}{2})

Then solve.

(\frac{6}{2}, \frac{-6}{2})

(3, -3)

If you'd like to check the other midpoint:

Take the points, (8, 3) and (-2, -9)

(\frac{8 - 2}{2}, \frac{3 - 9}{2})

Then solve.

(\frac{6}{2} , \frac{-6}{2})

(3, -3)

They're the same, so that answer is correct.

Hope this helps!

8 0
3 years ago
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