Answer:
7
Step-by-step explanation:
We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.
__
Let the thousands digit be 'd'. Then we want to find the integer solutions to ...
n -1000d = n/9
n -n/9 = 1000d . . . . . . add 1000d -n/9
8n = 9000d . . . . . . . . multiply by 9
n = 1125d . . . . . . . . . divide by 8
The values of d that will give a suitable 4-digit value of n are 1 through 7.
When d=8, n is 9000. Removing the 9 gives 0, not 1000.
When d=9, n is 10125, not a 4-digit number.
There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.
Step-by-step explanation:
3x(x2 + 2x – 6) + 4(x2
– 6x + 2)
We know, distributive property: a(b + c) = ab + ac
4(x + 2) = 4x + 8
In short, Your Answer would be Option B
Hope this helps!
Answer:
b = d -wn
Step-by-step explanation:
b = d -wn
Here, n is an independent variable and b is an dependent variable in an linear relation, and d and w are two constant values.
Hope it will find you well.
