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bekas [8.4K]
3 years ago
8

A whole number has the first four odd prime numbers as its factors. What is the smallest value this whole number could be?

Mathematics
2 answers:
PIT_PIT [208]3 years ago
7 0

Answer:

3×5×7×11=1155

a.1155 the answer

liberstina [14]3 years ago
5 0

Answer:

d. 210

Step-by-step explanation:

First four distinct prime numbers = 2,3,5,7

2×3×5×7 = 210

HOPE IT HELPS!!

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Midpoint formula : (x1 + x2) / 2, (y1 + y1) / 2
(4,1)....x1 = 4 and y1 = 1
(x,y)....x2 = x and y2 = y
sub
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4 + x = 3 * 2
4 + x = 6
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3 years ago
AXY Zand AABCare similar triangles. Given the dimensions shown in the diagram, what is the
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Answer:

3.528

Step-by-step explanation:

First, you need to determine the scale factor. Divide one side in the larger triangle by the corresponding side in the smaller triangle. For example, 8/2. This would give you a scale factor of 2. Then you can reverse the process with the dimensions you need to get the area. The height of the larger triangle is 3.36, so to find the height of the smaller one, you divide it by 2, or the scale factor, to get the height of the smaller triangle which is 1.68. Next, you can solve for area of triangle using a=bh/2, so 4.2*1.68/2=a = 3.528.

6 0
3 years ago
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a_sh-v [17]

Answer:

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Step-by-step explanation:

d for 1 and a for 2

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