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3 years ago

PLEASE CHACK MY ANSWER!!!!!!!!!!!!!! ITS EASY BUT I JUST DONT GET IT!!!

Mathematics

1 answer:

wolverine [178]3 years ago

3 0

Answer:

B) Yes- The scale factor is 2 and all coordinates increase by 2

Step-by-step explanation:

4/2 = 2

8/4 = 2

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When we plot all the points that satisfy an equation or inequality we what it?

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When you GRAPH an equation or inequality you plot all of the points that satisfy it.

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3 years ago

Is y=19x - 5 proportional

cricket20 [7]

Answer:

yes

Step-by-step explanation:

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3 years ago

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What two nonnegative real numbers with a sum of 60 have the largest possible product?

kogti [31]

The biggest possible real number = 60 ÷ 2 = 30

30 + 30 = 60

Largest Product = 30 x 30 = 900

Answer: The two numbers are 30 and 30.

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3 years ago

EXTRA POINTS

hram777 [196]

Answer:

Step-by-step explanation:

The volume of the pyramid = (1/3)*area of base *height

= (1/3)*10*24*13 = 1040 cubic units.

The total surface area = area of rectangular base + area of 2 isosceles triangles with a base of 24 units + area of 2 isosceles triangles with a base of 10 units.

Area of rectangular base = 24*10 = 240 sq units.

The slant height of isosceles triangles with a base of 24 units = [(10/2)^2+13^2]^0.5 = [25+169]^0.5 = 194^0.5 = 13.92838828 units.

The area of 2 isosceles triangles with a base of 24 units 2*24*13.92838828/2 = 334.2813187 sq units.

The slant height of isosceles triangles with a base of 10 units = [(24/2)^2+13^2]^0.5 = [144+169]^0.5 = 194^0.5 = 17.69180601 units.

The area of 2 isosceles triangles with a base of 10 units 2*10*17.69180601/2 = 176.9180601 sq units.

The total surface area of the pyramid = 240 + 334.2813187 + 176.9180601 = 591.9731247 sq units.

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3 years ago

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A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on

SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

$Z_{1-\alpha /2}= Z_{0.95}= 1.645$

[10.41±1.645* $(\frac{3.71}{\sqrt{28} } )$ ]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0

4 years ago