Each time they assume the sum<span> is </span>rational<span>; however, upon rearranging the terms of their equation, they get a contradiction (that an </span>irrational number<span> is equal to a </span>rational number<span>). Since the assumption that the </span>sum of a rational<span> and </span>irrational number<span> is </span>rational<span>leads to a contradiction, the </span>sum<span> must be </span>irrational<span>.</span>
Answer:
x = 6 sqrt(3)
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
6^2+ x^2 = 12^2
36 + x^2 = 144
Subtract 36 from each side
x^2 = 144-36
x^2 =108
Take the square root of each side
sqrt(x^2) = sqrt(108)
x = sqrt(36*3)
x = 6 sqrt(3)
Answer: Attached.
Step-by-step explanation:
Either solve the equations directly, or graph them and look for the point of intersection.
12) the product of ⅛ and a number
also the quotient of a number and y
16). the quotient of the fourth power of a number and 9
The equation would be 30+3m=162 then you solve the problem
