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djverab [1.8K]
4 years ago
5

Hi, how many 2 inch segments are there in 12ft? Thank you for the help :)

Mathematics
1 answer:
marin [14]4 years ago
7 0
There are 72 segments
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A sample of 12 radon detectors of a certain type was selected, and each was exposed to 100 pCI/L of radon. The resulting reading
valkas [14]

Answer:

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

p_v =2*P(t_{11}  

Step-by-step explanation:

1) Data given and notation  

Data: 105.6, 90.9, 91.2, 96.9, 96.5, 91.3, 100.1, 105.0, 99.6, 107.7, 103.3, 92.4

We can calculate the sample mean and deviation for this data with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

The results obtained are:

\bar X=98.375 represent the sample mean  

s=0.6.109 represent the sample standard deviation  

n=12 sample size  

\mu_o =100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 100pCL/L, the system of hypothesis are :  

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

4) P-value  

First we need to find the degrees of freedom for the statistic given by:

df=n-1=12-1=11

Since is a two sided test the p value would given by:  

p_v =2*P(t_{11}  

5) Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significant different from 100 at 5% of significance.  

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(x-5)2/5=4 Solve the equation.
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Answer: x=15

Step-by-step explanation:

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Your answer is 3. Y=2x-5
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If Ashley is in the 85th percentile and the mean of her test scores is 180 with a standard deviation of 15, which of the followi
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<span>B would be the most appropriate response for this. We don't need to worry about Ashley being in the 85th percentile, that is just extra information they have provided us. What we need to look at is her mean test score is 180, so that is the average score she normally gets on her tests, but then they say she has a standard deviation of 15 which means her scores are normally no lower than 165 and no higher than 195 because she normally doesn't deviate or change her score more than 15 points for her normal 180. So if you take 180 minus 15 you get 165 and if you take 180 plus 15 you get 195, therefore we can determine that the most appropriate answer would be between 165 and 195. The only option that fits in this category is B 185</span>
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Answer: I think it’s A if I am incorrect I am very sorry

Step-by-step explanation:

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