Answer:
47.1 ft
Step-by-step explanation:
C = πd
C = 3.14 · 15
C = 47.1
C ≈ 47.1 ft
Answer:
What strip?
Step-by-step explanation:
Step-by-step explanation:
Realize that:
speed = distance / time and thus
time = distance / speed
Then the whole journey of 40/60 hours is the sum of (let's call them t1 and t2)
cycling: t1 = 2/y hours
running: t2 = 4/(y-4) hours
so we must simplify t1+t2=40 minutes (a.k.a. 4/6 hours):
2/y + 4/(y-4) = 4/6
let's multiply the first term by (y-4)/(y-4) and the second term by (y/y):
![\frac{2(y-4)}{y(y-4)} + \frac{4y}{y(y-4)} = \frac46](https://tex.z-dn.net/?f=%5Cfrac%7B2%28y-4%29%7D%7By%28y-4%29%7D%20%2B%20%5Cfrac%7B4y%7D%7By%28y-4%29%7D%20%3D%20%5Cfrac46)
since they now share a common denominator:
![\frac{2(y-4) + 4y}{y(y-4)} = \frac46](https://tex.z-dn.net/?f=%5Cfrac%7B2%28y-4%29%20%2B%204y%7D%7By%28y-4%29%7D%20%3D%20%5Cfrac46)
![\frac{6y-8}{y(y-4)} = \frac46](https://tex.z-dn.net/?f=%5Cfrac%7B6y-8%7D%7By%28y-4%29%7D%20%3D%20%5Cfrac46)
cross-products:
![6 (6y-8) = 4y(y-4)](https://tex.z-dn.net/?f=6%20%286y-8%29%20%3D%204y%28y-4%29)
further simplification:
![36y - 48 = 4y^2 - 16y](https://tex.z-dn.net/?f=36y%20-%2048%20%3D%204y%5E2%20-%2016y)
![4y^2 - 52y + 48 = 0](https://tex.z-dn.net/?f=4y%5E2%20-%2052y%20%2B%2048%20%3D%200)
![y^2 - 13y + 12 = 0](https://tex.z-dn.net/?f=y%5E2%20-%2013y%20%2B%2012%20%3D%200)
q.e.d.
Answer:
4
Step-by-step explanation:
Answer:
• Random sampling [ Probability and statistics method ]
Step-by-step explanation:
• This method is easier and saves time.
By probability, a person whose height is to be recorded will be chosen randomly. This will be done on approximately 40% members.
By statistical step, we'll feed results into distribution table. Then we'll find the mean height.
![{ \boxed{ \rm{mean \: height = \frac{ \sum \: f(n)}{n} }}}](https://tex.z-dn.net/?f=%7B%20%5Cboxed%7B%20%5Crm%7Bmean%20%5C%3A%20height%20%3D%20%20%5Cfrac%7B%20%5Csum%20%5C%3A%20f%28n%29%7D%7Bn%7D%20%7D%7D%7D)
• f of n is product of frequency and respective height bracket
• n is the number of samples.