Answer:
-25 plug in 6 for x and minus one
Step-by-step explanation:
Distribute the 5 to each of the numbers so you should get 5x+5+5x+5+5x+35. after this you should combine like terms, all of the 5’s & the 35 and 5x’s. you should have 15x+45. then you divide 45 by the 15 and you should get x=3
IMPORTANT:
If you're trying to factor a quadratic in Algebra I:There are no two integers that can solve this problem!
Your quadratic is <em>prime</em>!
If you're trying to solve a quadratic (find x):The factoring approach will not work for the same reasons listed above.
Try using splitting the middle or the quadratic formula instead.
Here's how you would solve it from a more advanced approach.
If you don't know what this stuff is, just ignore it.
ab = -18, a + b = -9
Find a in terms of b.
a = -9-b
Substitute this for a in the first equation.
(-9-b)b = -18
-9b-b² = -18
Multiply everything by -1 to get rid of all these negative signs.
b² + 9b = 18
Bring over that 18.
b² + 9b - 18 = 0
Apply the quadratic formula.
(a = 1, b = 9, c = -18)

If you need to write two distinct numbers, just write out one with a + and one with a - in place of the plus-minus sign.
Answer:
As far as i know you should go for LCM that would be more convenient and easy to do
There is no solution.
Step-by-step explanation:
Given:
y = 2x + 1
4x - 2y = 4
Substitute y = 2x + 1 into 4x - 2y = 4
4x - 2(2x + 1) = 4
4x - 4x - 2 = 4
0x = 4 + 2
0x = 6
Anything to the multiple of zero is zero. Hence 0x = 0, and 0 ≠ 6
So there is no solution to the equation.