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lianna [129]
3 years ago
9

The product of 7/16,4/3, and 1/2 is

Mathematics
2 answers:
ElenaW [278]3 years ago
8 0

Answer:

\frac{7}{24}

Step-by-step explanation:

\frac{7}{16} * \frac{4}{3}=\frac{28}{48}

Just multiply 7 and 4, then multiply 16 and 3.

You get 28/48. Now multiply this by 1/2.

\frac{28}{48}*\frac{1}{2}  =\frac{28}{96}

Simplify by dividing both numbers by 4 because 4 is the GCF.

28/4=7

96/4= 24

You get 7/24

I hope this helps!

Lady_Fox [76]3 years ago
4 0
The answer would be 7/24.
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What is the axis of symmetry and vertex for the function f(x) = 3(x – 2)2 + 4?
Gnesinka [82]
The axis of symmetry is 2 and the vertex is (2, 4).
8 0
3 years ago
At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed st
EastWind [94]

<u>Answer:</u>

C. Left-handed: 48, Right-handed: 504

D. Left-handed: 30, Right-handed: 315

<u>Step-by-step explanation:</u>

We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.

Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.

Ratio of right handed to left handed students at East Middle School = \frac{609}{58} = 10.5

Checking for ratios of the given options:

A. \frac{483}{42} =11.5

B. \frac{378}{28} =13.5

C. \frac{504}{48} =10.5

D. \frac{560}{56} =10

E. \frac{315}{30} =10.5

Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.

7 0
2 years ago
Read 2 more answers
QUESTION 1
Kitty [74]

It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)

The cosine of the angle between the vectors can be obtained from the dot product identity,

<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)

For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is

<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

==>   <em>W</em> ≈ 5.12 J

(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).

3 0
3 years ago
225 to 270 I need help please help me
vagabundo [1.1K]
Wheres the picture or the problem????
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=6-3%2F4x%2B1%2F3%3D1%2F2x%2B5" id="TexFormula1" title="6-3/4x+1/3=1/2x+5" alt="6-3/4x+1/3=1/2x
Vikki [24]

Answer:

X=1 1/3 or

X=1.3

Step-by-step explanation:

Hope I helped u

6 0
2 years ago
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