Question

If a rectangle has the sides 5x-3 and 6x-4 what is the area and perimeter

Answer 1

Step-by-step explanation:

$A = lw$

$A=(5x-3)(6x-4)$

$A=30x^2-20x-18x+12$

$A=30^2-28x+12$

$P=2(l + w)$

$P = 2(5x - 3 + 6x - 4)\\P=2(x-7)\\P=2x-14$

Answer 2

Answer:

$Perimeter = 22x - 14$

$Area = 30 {x}^{2} - 38x + 12$

Step-by-step explanation:

Length of rectangle (l) = 5x - 3

Weidth of rectangle (w) = 6x - 4

Perimeter of the rectangle = $2(l + w)$

$= > 2(5x - 3 + 6x - 4)$

$= > 2(11x - 7)$

$= > 22x - 14$

Area of the rectangle = $l \times w$

$= > (5x - 3)(6x - 4)$

$= > 5x(6x - 4) - 3(6x -4)$

$= > 30 {x}^{2} - 20x - 18x + 12$

$= > 30 {x}^{2} - 38x + 12$