If f(x) = (6x-11), then f(-6) = -47.
We are provided in the question statement with a function "f(x)" whose output is a polynomial of 1 variable and degree 1.
To obtain the value of f(-6) from the output polynomial of the function f(x), we will simply need to substitute (-6) as the value of x in the polynomial and calculate the final value.
So,
![f(-6)=[(6*(-6))-11]\\or, f(-6)=(-36-11)\\or, f(-6)=-(36+11)\\or, f(-6) =-47](https://tex.z-dn.net/?f=f%28-6%29%3D%5B%286%2A%28-6%29%29-11%5D%5C%5Cor%2C%20f%28-6%29%3D%28-36-11%29%5C%5Cor%2C%20f%28-6%29%3D-%2836%2B11%29%5C%5Cor%2C%20f%28-6%29%20%3D-47)
Hence, f(-6) = -47.
- Polynomial: In mathematics, an expression of more than two algebraic terms, especially the sum of several terms that contain the same variable(s) of different powers and individual, distinct co-efficients.
- Function: In Mathematics, a function is an operator which on taking input, provides a certain output.
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There would be 1/12 of the cake left.
Just multiply the two, your answer should be 21.06
The diagram which the locus of all the points in the plane that are 3cm away from a single point A is Option B
<h3>What is a locus?</h3>
A locus is defined as a set of points, which satisfies a given condition or situation for a shape or a figure.
It is important to note that:
- The locus of points in a plane that are all the same distance from a single point is a circle with radius, r
- A circle is the locus of all the points in the plane which are equidistant from the points in that plane
- The locus of all points equidistant from the vertices of a square is a straight line that is perpendicular to the plane of the square, through the center of the square
We can see that for a circle, the locus of all points in the plane is the radius equidistant from that line.
Thus, the diagram which the locus of all the points in the plane that are 3cm away from a single point A is Option B
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