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Find the 28th term of the arithmetic sequence

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tamaranim1 [39]3 years ago

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Ain’t really sure but I’m it’s ( C

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P(I) = 0.60; P(II) = 0.40;

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The probability that the phone came from factory II, given that is not defective, is determined by the probability of a phone from factory II not being defective divided by the probability of a phone not being defective.

$P(II|not) = \frac{P(II)*P(not_{II})}{P(II)*P(not_{II})+P(I)*P(not_{I})}\\P(II|not) = \frac{0.40*0.80}{0.40*0.80+0.60*0.90}\\ P(II|not) =0.3721 = 37.21\%$

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