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Bogdan [553]
3 years ago
14

Find the 28th term of the arithmetic sequence

Mathematics
1 answer:
tamaranim1 [39]3 years ago
8 0
Ain’t really sure but I’m it’s ( C
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_ 1. If U = {1,2,3,4,5) and A= {2,4} then A' should be?
kirza4 [7]

If U={1,2,3,4,5) and A={2,4) then A' should be

Ans» d.{1,3,5}

4 0
3 years ago
74% of freshmen entering public high schools in 2006 graduated with their class in 2010. A random sample of 81 freshmen is selec
Assoli18 [71]

Answer: Probability that the proportion of students who graduated is greater than 0.743 is P = 0.4755

Step-by-step explanation:

Given that,

Probability of freshmen entering public high schools in 2006 graduated with their class in 2010, p = 0.74

Random sample of freshman, n = 81

Utilizing central limit theorem,

P(\hat{p}

So,

(P(\hat{p}>0.743) = P(Z>0.743 - \frac{0.74}{\sqrt{\frac{0.74(1-0.74)}{81} }  } )

= P( Z > 0.0616)

= 0.4755 ⇒ probability that the proportion of students who graduated is greater than 0.743.

7 0
3 years ago
40,-20,10,-5,__,__,__<br> What are the next three numbers.
valkas [14]

Answer:

2.5, -1.25, 0.625

Step-by-step explanation:

4 0
3 years ago
Item 4 Find the median, first quartile, third quartile, and interquartile range of the data. 132,127,106,140,158,135,129,138 med
Ket [755]

Answer:

133.5, 127.5, 139.5, 12

Step-by-step explanation:

order data:

106, 127, 129, 132, 135, 138, 140, 158

Median:

The middle number: (8+1)/2 = 4.5 between the 4&5 numbers

= (135-132)/2= 1.5

1.5 + 132 = 133.5

lower quartile (1st quartile):

(8+1)/4 = 2.25 between the 2&3 numbers

(129+127)/4=0.5

0.5+127 = 127.5

upper quartile(3rd quartile):

(8+1)/4 x3 = 6.75 between the 6&7 numbers

(140-138)/4 x3 = 1.5

1.5 + 138 =139.5

Interquartile range:

139.5-127.5= 12

hope this helps

4 0
3 years ago
How do I solve 6x—20=
REY [17]

Answer:

Can not be determined

Step-by-step explanation:

regularly, you would +20 to both sides, but without a full =, you cant solve. If the equation is 6x-20=0, x would equal 3 2/6.

Hope this helps!

4 0
3 years ago
Read 2 more answers
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